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dem82 [27]
3 years ago
8

Why is subtracting an expression similar to distributing a –1? Use the drop-down menus to explain your answer.

Mathematics
1 answer:
anygoal [31]3 years ago
8 0

Answer:

When subtracting expressions, we are applying the distributive property, where a multiple of an expression in brackets is applied to to each term.

e.g.

a(x + y) = ax + ay

In the case of subtracting an expression, we're doing the same thing, but in the example above, "a" would be equal to -1.

(a + b) - (c + d) ≡ (a + b) + -1(c + d)

And so the negative one is distributed across the terms within the brackets.

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Find each answer mentally.
trapecia [35]

Answer:

1: 1/4 dollars or .25 dollars or 25%

2: 150 cents

3: 100 cents

4: 1/100 dollars, or 0.01 dollars, or 1%

Step-by-step explanation:

8 0
3 years ago
Laila and Bryson are finding the slope of a line that passes through the two points (3, -5) and (-4, -6). Who is correct and why
snow_tiger [21]
Slope formular = (y2-y1)/(x2 - x1)
so
slope = (-6 +5)/(-4-3) 
slope = -1/-7
slope = 1/7

answer
Laila is correct
3 0
3 years ago
Here’s question 2 once again I’ll give brainlest
andreev551 [17]

Answer:

51

Step-by-step explanation:

sum of squares of legs, equal to the square of the hypotenuse.

24²+45²=c²

576+2,025=√2,601

√2,601=51

6 0
2 years ago
A simple random sample of 100 observations was taken from a large population. The sample mean and the standard deviation were de
olga2289 [7]

Answer:

Se=1.2

Step-by-step explanation:

The standard error is the standard deviation of a sample population. "It measures the accuracy with which a sample represents a population".

The central limit theorem (CLT) states "that the distribution of sample means approximates a normal distribution, as the sample size becomes larger, assuming that all samples are identical in size, and regardless of the population distribution shape"

The sample mean is defined as:

\bar X =\frac{\sum_{i=1}^n x_i}{n}

And the distribution for the sample mean is given by:

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

Let X denotes the random variable that measures the particular characteristic of interest. Let, X1, X2, …, Xn be the values of the random variable for the n units of the sample.

As the sample size is large,(>30) it can be assumed that the distribution is normal. The standard error of the sample mean X bar is given by:

Se=\frac{\sigma}{\sqrt{n}}

If we replace the values given we have:

Se=\frac{12}{\sqrt{100}}=1.2

So then the distribution for the sample mean \bar X is:

\bar X \sim N(\mu=80,Se=1.2)

5 0
3 years ago
HELP ME FAST!!!!!Plz my computers about to go dead ​
Delvig [45]
It’s 4/15
Answer = 3 3/4
I hope that helps :)
4 0
2 years ago
Read 2 more answers
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