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gogolik [260]
3 years ago
5

Two objects attract each other with a gravitational force of 25 Newton’s from the given distance. If the distance between the tw

o objects is reduced by a factor of 5, what is the changed force of attraction between them?
Physics
2 answers:
Elenna [48]3 years ago
8 0
The new change of force of attraction will increase by the factor of 5^2
bearhunter [10]3 years ago
5 0

The changed force of attraction between them is 625 newtons.

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Explanation:

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Thus, we can conclude that the following statements are true.

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2 years ago
a cement block accidentally falls from rest from the ledge of a 80.6-m-high building. When the block is 10.8 m above the ground,
fomenos

Answer:

0.229 seconds

Explanation:

Given:

y₀ = 80.6 m

v₀ = 0 m/s

a = -9.8 m/s²

We need to find the difference in times when y = 10.8 m and y = 2.10 m.

When y = 10.8 m:

y = y₀ + v₀ t + ½ at²

10.8 = 80.6 + (0) t + ½ (-9.8) t²

10.8 = 80.6 − 4.9 t²

4.9 t² = 69.8

t = 3.774

When y = 2.10 m:

y = y₀ + v₀ t + ½ at²

2.10 = 80.6 + (0) t + ½ (-9.8) t²

2.10 = 80.6 − 4.9 t²

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The man has 0.229 seconds to get out of the way.

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