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jok3333 [9.3K]
3 years ago
14

I need guidance pls

Physics
1 answer:
seropon [69]3 years ago
8 0
The slowest line is the solid line and the fastest is the dotted line that crosses the solid line
for future reference you just need to find the slope or the line which is traveling most vertical
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I’m not sure how to do this
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4 years ago
How much force is required to accelerate a 57 kg skier 4 m/s2? ______ N (do not write anything except the number)
vfiekz [6]

The amount of force required to accelerate 57kg skier with an acceleration of 4m/s² is 228N.

<h3>How to calculate force?</h3>

Force is a physical quantity that denotes ability to push, pull, twist or accelerate a body and which has a direction and is measured in a unit dimensioned in mass × distance/time².

The force applied on an object can be calculated using the following formula:

Force = mass × acceleration

According to this question, a skier with mass 57kg accelerates at 4m/s². The force required can be calculated as follows:

Force = 57kg × 4m/s²

Force = 228N

Therefore, the amount of force required to accelerate 57kg skier with an acceleration of 4m/s² is 228N.

Learn more about force at: brainly.com/question/1046166

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2 years ago
Of all fresh water available how much of it is ready for use by humans
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3 years ago
. Two identical blocks, each of mass M, are connected by a massless string over a pulley of radius R and moment of inertia I. Th
Dima020 [189]

The angular acceleration of a pulley is described under the equation,

\theta = (0.5) \alpha t^2

So things clearing,

\alpha = \frac{ 2\theta}{t^2}

b) For point B it is necessary to make a sum of Forces,

\sum F=0

In this way,

Mg - T_1 = Ma

T_1 = Mg - Ma (1)

For block 2, we have the following relationship,

T_2 = Ma (2)

So,

T_1 - T_2 = I \frac{a}{R} (3)

Substituting (1) and (2) in (3)

Mg - Ma - Ma = I \frac{a}{R}

So,

a = \frac{2\theta R}{t^2}

<em>**Note that</em> \alpha R = a

c) For this point we need to use (1)

T1 = Mg - Ma = Mg - \frac{M^2\theta R}{t^2}

using (2)

RT_2=RT_1-I\alpha

T_2= \frac{RM(g-\frac{2\theta R}{t^2})-I\frac{2\theta}{t^2}}{R}

T_2=\frac{RMgt^2-2R^2M\theta-2t\theta}{Rt^2}

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