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masha68 [24]
3 years ago
5

Can some help me pls find the angle measure for each one

Mathematics
2 answers:
Marianna [84]3 years ago
8 0

Answer:

1 = 140 2 = 70

Step-by-step explanation

1 is 140 because it is the same as 140 and 2 is 70 because it is the same angle as 70.

Travka [436]3 years ago
3 0

Answer:

Angle 1 is: 140

Angle 2 is: 70

Step-by-step explanation:

Both the angles are corresponding angles. This means the other angle is congruent (equal).

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Find the surface area of the rectangular prism:​
sergey [27]

Answer: 430 cm²

Step-by-step explanation:

1) Front x Back=  15 x 7  x 2= 210 (We do time 2 because there are two of the same shapes ex. there are two squares that are both 16 ft so just do 16 x 2)

2) Right x Left=  7 x 5 x 2 = 70

3) Top x Bottom=  15 x 5 x2 = 150

4) Add. 150 + 210 + 70 = 430 cm²

Hope that helped! :)

4 0
3 years ago
It snowed 134.46 inches on Monday and 8.3 inches on Tuesday. How much did it snow on Monday and Tuesday combined?
kkurt [141]

Answer

142.76

Step-by-step explanation:

4 0
3 years ago
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Interest rates of 5%,6%,8%, earned on investments of $13,000,$12,000,$4,000. Calculate total amount of interest earned
Mariana [72]
13,000*0.05+12,000*0.06+4,000*0.08=1,690.00
7 0
4 years ago
Emma has $0.95 in dimes and nickles. She has five more dimes than nickles. How many coins of each type does she have?
Licemer1 [7]

Answer:

3 nickels and 8 dimes

Step-by-step explanation:

3 nickels equals 15

3 plus 5 equals 8

8 dimes equals 80

80 plus 15 equals 95

so ur answer is 3 nickels and 8 dimes

8 0
3 years ago
Dy/dx = 2xy^2 and y(-1) = 2 find y(2)
Anarel [89]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2887301

—————

Solve the initial value problem:

   dy
———  =  2xy²,      y = 2,  when x = – 1.
   dx


Separate the variables in the equation above:

\mathsf{\dfrac{dy}{y^2}=2x\,dx}\\\\
\mathsf{y^{-2}\,dy=2x\,dx}


Integrate both sides:

\mathsf{\displaystyle\int\!y^{-2}\,dy=\int\!2x\,dx}\\\\\\
\mathsf{\dfrac{y^{-2+1}}{-2+1}=2\cdot \dfrac{x^{1+1}}{1+1}+C_1}\\\\\\
\mathsf{\dfrac{y^{-1}}{-1}=\diagup\hspace{-7}2\cdot \dfrac{x^2}{\diagup\hspace{-7}2}+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{y}=x^2+C_1}

\mathsf{\dfrac{1}{y}=-(x^2+C_1)}


Take the reciprocal of both sides, and then you have

\mathsf{y=-\,\dfrac{1}{x^2+C_1}\qquad\qquad where~C_1~is~a~constant\qquad (i)}


In order to find the value of  C₁  , just plug in the equation above those known values for  x  and  y, then solve it for  C₁:

y = 2,  when  x = – 1. So,

\mathsf{2=-\,\dfrac{1}{1^2+C_1}}\\\\\\
\mathsf{2=-\,\dfrac{1}{1+C_1}}\\\\\\
\mathsf{-\,\dfrac{1}{2}=1+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-1=C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-\dfrac{2}{2}=C_1}

\mathsf{C_1=-\,\dfrac{3}{2}}


Substitute that for  C₁  into (i), and you have

\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}}\\\\\\
\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}\cdot \dfrac{2}{2}}\\\\\\
\mathsf{y=-\,\dfrac{2}{2x^2-3}}


So  y(– 2)  is

\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot (-2)^2-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot 4-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{8-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{5}}\quad\longleftarrow\quad\textsf{this is the answer.}


I hope this helps. =)


Tags:  <em>ordinary differential equation ode integration separable variables initial value problem differential integral calculus</em>

7 0
3 years ago
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