The answer would be 13.75 Thats the effective interest rate. (btw this question is about me lol)
Step-by-step explanation:
100% = 2,478,846
1% = 100%/100 = 2,478,846/100 = 24,788.46
how many % are 1,885,128 ?
we need to see how often 1% fits into that amount.
1,885,128 / 24,788.46 = 76.04861294... %
so, the rounded answer is
76.05%
(i) Use the formula for the determinant of a 2×2 matrix.
(ii) The adjugate matrix is the transpose of the cofactor matrix of A. (These days, the "adjoint" of a matrix X is more commonly used to refer to the conjugate transpose of X, which is not the same.)
The cofactor of the (i, j)-th entry of A is the determinant of the matrix you get after deleting the i-th row and j-th column of A, multiplied by . If C is the cofactor matrix of A, then
Then the adjugate of A is the transpose of C,
(iii) The inverse of A is equal to 1/det(A) times the adjugate:
(iv) The system of equations translates to the matrix equation
Multiplying both sides on the left by the inverse of A gives
Answer:
a) 0.216
b) 0.1587
c) 0.369
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 12.2 grams
Standard Deviation, σ = 2.8 grams
We are given that the distribution of weights of impurities per bag is a bell shaped distribution that is a normal distribution.
Formula:
a) P(contains less than 10 grams of impurities)
P(x < 10)
Calculation the value from standard normal z table, we have,
b) P(contains more than 15 grams of impurities)
P(x > 15)
Calculation the value from standard normal z table, we have,
c) P(contains between 12 and 15 grams of impurities)
d) The mean divide the data in exactly two parts. Since 15 is farther away from the mean as compared to 10, the probability obtained in part (b) is smaller as compared to probability obtained in part (a).
Because the student scored 73/100 on the first test, their current average is 73%.
To calculate the avergae with the next test score, you add both percentages the student gets together and then divide by 2.
79 = (73 + x) / 2
Multiply by 2 on both sides
158 = 73 + x
Subtract 73 on both sides
x = 85
So the student needs to get at least an 85/100 on the next test to maintain a 79 average.