Answer:
b. Mg & Cl
a. transferred
46
Explanation:
Ionic bonds form between metals and non-metals when electrons are transferred from one specie to another.
- The electrostatic attraction from the resulting ions forms the ionic bonds.
- A metal is electropositive and will readily donate electrons
- A non-metal is electronegative and will accept electrons.
- This creates two oppositely charge ions that attracts by means of ionic bonding.
Since Mg and Cl are the only metal - non-metal pair, and ionic bond will form between them.
2.
In the specie;
₄₇Ag¹⁺
47 is the atomic number of the element Ag.
The atomic number is the number of protons in an atom. For a specie in neutral state, the number of protons and electrons are the same.
- When an atom loses electron, it becomes positively charged.
- Here Ag has lost one electron and then, the number of electrons becomes 46.
- The number of protons is still 47
The glass rod is a piece of laboratory equipment and it is used for the mixing of <span> chemicals and other liquids.</span>
Answer:
% = 76.75%
Explanation:
To solve this problem, we just need to use the expressions of half life and it's relation with the concentration or mass of a compound. That expression is the following:
A = A₀ e^(-kt) (1)
Where:
A and A₀: concentrations or mass of the compounds, (final and initial)
k: constant decay of the compound
t: given time
Now to get the value of k, we should use the following expression:
k = ln2 / t₁/₂ (2)
You should note that this expression is valid when the reaction is of order 1 or first order. In this kind of exercises, we can assume it's a first order because we are not using the isotope for a reaction.
Now, let's calculate k:
k = ln2 / 956.3
k = 7.25x10⁻⁴ d⁻¹
With this value, we just replace it in (1) to get the final mass of the isotope. The given time is 1 year or 365 days so:
A = 250 e^(-7.25x10⁻⁴ * 365)
A = 250 e^(-0.7675)
A = 191.87 g
However, the question is the percentage left after 1 year so:
% = (191.87 / 250) * 100
<h2>
% = 76.75%</h2><h2>
And this is the % of isotope after 1 year</h2>
Partial mass of C, 12*2 = 24
Partial mass of H, 1*5 = 5
Partial mass of N, 14
Partial mass of O, 16
Now, total molar mass would be 24+5+14+16 = 59
mass % of carbon = 24 * 100 / 59 = 40.67%