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Novay_Z [31]
3 years ago
10

Select the true statements about SDS‑PAGE, a method of separating proteins. Assume that SDS‑PAGE is performed under reducing

conditions.
a. Proteins are separated in a polyacrylamide gel matrix.
b. Protein‑SDS complexes have similar mass to charge ratios; therefore, separation is by size.
c. Proteins are visualized using a dye that binds to the gel matrix, but not to proteins.
d. Smaller proteins migrate faster through the polyacrylamide gel.
e. Sodium dodecyl sulfate binds proteins, resulting in protein‑SDS complexes that are similar in size.
f. Protein‑SDS complexes migrate toward the negative electrode.
Chemistry
1 answer:
Tanzania [10]3 years ago
6 0
Proteins are separated
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12.7 l of argon at 33°c and 735 torr are dissolved in enough water to give a final volume of 0.750 l. what is the molarity of th
Damm [24]

The molarity of the resulting solution is 0.65 M.

<h3>Which molarity is it?</h3>
  • To be able to comprehend what we mean by the molarity of a solution, we must first go back in time. We are aware that molarity refers to the concentration of the component in the solution. In this situation, it's important to be aware that the molarity can only be represented in terms of moles per litre.
  • The number of moles of the gas must now be determined, and this can only be done by applying the ideal gas equation, which is what we will be able to accomplish in this issue.

PV = nRT

Pressure is P.

Volume is V.

The number of moles is n.

Gas constant R

Temperature is T

n = PV/RT

n = 0.97 * 12.7/0.082 * 306

n = 12.3/25.1

N=0.49 moles.

Number of Mole/Volume Equals Molarity of the Solution

0.49 moles/0.750 liters

= 0.65 M

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7 0
1 year ago
I need help asap please
mr_godi [17]

Answer:

its the second option

Explanation:

pls mark BRAINLIEST

8 0
3 years ago
Since vinegar is 5% acetic acid and 95% water, find the mole ratio of acetic acid to water in 100 g of vinegar? Hint: Instead of
Oksanka [162]

The mole ratio of acetic acid to water in 100 g of vinegar is 0.015 : 0.985.

<h3>What is the mole ratio of acetic acid to water in 100 g of vinegar?</h3>

The mole ratio of acetic acid to water in 100 g of vinegar is determined from their percentage composition.

The percentage composition of acetic acid and water in vinegar is 5% acetic acid and 95% water.

In 100 g of vinegar, there are 5 g of acetic acid and 5 g of water.

Moles = mass/molar mass

molar mass of acetic acid = 62 g/mol

molar mass of water = 18 g/mol

moles of vinegar = 5/62 = 0.08

moles of water = 95/18 = 5.28

total moles = 5.36

Mole ratio of vinegar to water = 0.08/5.36 : 5.28/5.36

Mole ratio of vinegar to water = 0.015 : 0.985

In conclusion, the mole ratio is determined from the percentage composition of acetic acid and water in vinegar.

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7 0
2 years ago
Explain how friction and mass affect the motion of an object.
agasfer [191]

Answer: Ithink that the mass is the one that affects the friction.

Explanation:

8 0
3 years ago
When 2,2-dimethylbutane is subjected to free-radical chlorination, ________ distinct monochlorinated products are possible and _
malfutka [58]

Answer:

See the explanation

Explanation:

In this case, we have to remember that in the <u>monochlorination products</u> we only have to add one "Cl" with this in mind, we can have several options.

<u>a) 1-chloro-2,2-dimethylbutane</u>

<u>b) (R)-3-chloro-2,2-dimethylbutane</u>

<u>c) (S)-3-chloro-2,2-dimethylbutane</u>

<u>d) 1-chloro-3,3-dimethylbutane</u>

Additionally, from these 4 molecules, we will have 2 enantiomers. (R)-3-chloro-2,2-dimethylbutane and (S)-3-chloro-2,2-dimethylbutane.

See figure 1

I hope it helps!

6 0
3 years ago
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