The molarity of the resulting solution is 0.65 M.
<h3>Which molarity is it?</h3>
- To be able to comprehend what we mean by the molarity of a solution, we must first go back in time. We are aware that molarity refers to the concentration of the component in the solution. In this situation, it's important to be aware that the molarity can only be represented in terms of moles per litre.
- The number of moles of the gas must now be determined, and this can only be done by applying the ideal gas equation, which is what we will be able to accomplish in this issue.
PV = nRT
Pressure is P.
Volume is V.
The number of moles is n.
Gas constant R
Temperature is T
n = PV/RT
n = 0.97 * 12.7/0.082 * 306
n = 12.3/25.1
N=0.49 moles.
Number of Mole/Volume Equals Molarity of the Solution
0.49 moles/0.750 liters
= 0.65 M
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The mole ratio of acetic acid to water in 100 g of vinegar is 0.015 : 0.985.
<h3>What is the mole ratio of acetic acid to water in 100 g of vinegar?</h3>
The mole ratio of acetic acid to water in 100 g of vinegar is determined from their percentage composition.
The percentage composition of acetic acid and water in vinegar is 5% acetic acid and 95% water.
In 100 g of vinegar, there are 5 g of acetic acid and 5 g of water.
Moles = mass/molar mass
molar mass of acetic acid = 62 g/mol
molar mass of water = 18 g/mol
moles of vinegar = 5/62 = 0.08
moles of water = 95/18 = 5.28
total moles = 5.36
Mole ratio of vinegar to water = 0.08/5.36 : 5.28/5.36
Mole ratio of vinegar to water = 0.015 : 0.985
In conclusion, the mole ratio is determined from the percentage composition of acetic acid and water in vinegar.
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Answer: Ithink that the mass is the one that affects the friction.
Explanation:
Answer:
See the explanation
Explanation:
In this case, we have to remember that in the <u>monochlorination products</u> we only have to add one "Cl" with this in mind, we can have several options.
<u>a) 1-chloro-2,2-dimethylbutane</u>
<u>b) (R)-3-chloro-2,2-dimethylbutane</u>
<u>c) (S)-3-chloro-2,2-dimethylbutane</u>
<u>d) 1-chloro-3,3-dimethylbutane</u>
Additionally, from these 4 molecules, we will have 2 enantiomers. (R)-3-chloro-2,2-dimethylbutane and (S)-3-chloro-2,2-dimethylbutane.
See figure 1
I hope it helps!