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3 years ago

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Select the true statements about SDSâ€‘PAGE, a method of separating proteins. Assume that SDSâ€‘PAGE is performed under reducing

conditions.
a. Proteins are separated in a polyacrylamide gel matrix.
b. Proteinâ€‘SDS complexes have similar mass to charge ratios; therefore, separation is by size.
c. Proteins are visualized using a dye that binds to the gel matrix, but not to proteins.
d. Smaller proteins migrate faster through the polyacrylamide gel.
e. Sodium dodecyl sulfate binds proteins, resulting in proteinâ€‘SDS complexes that are similar in size.
f. Proteinâ€‘SDS complexes migrate toward the negative electrode.

1 answer:

Tanzania [10]3 years ago

6 0

Proteins are separated

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Provide the nuclear equation for a decay of polonium-214

s344n2d4d5 [400]

The nuclear equation that describes the alpha decay of Polonium-210 can be written like this:
210/
84Po→206/82Pb+4/2 He

3 0

3 years ago

A block of iron has a mass of 150 g and a volume of 20 ml. What is the density of iron? *

shtirl [24]

Answer:

<h3>The answer is 7.50 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass of iron = 150 g

volume = 20 mL

We have

$density = \frac{150}{20} = \frac{15}{2} \\$

We have the final answer as

<h3>7.50 g/mL</h3>

Hope this helps you

4 0

3 years ago

Read 2 more answers

If a 95.27 mL sample of acetic acid (HC2H3O2) is titrated to the equivalence point with 79.06 mL of 0.113 M KOH, what is the pH

KATRIN_1 [288]

Answer:

8.73

Explanation:

The concentration of acetic acid can be determined as follows:

$M_1V_1 = M_2V_2\\(KOH) = (CH_3COOH)$

$M_{KOH}=0.113 M\\V_{KOH}=79.06 mL$

$V_{CH_3COOH}=95.27 \\\\M_{CH_3COOH)=?????$

$M_{CH3COOH} = \frac{M_{KOH}*V_{KOH}}{V_{CH_3COOH}}$

$M_{CH3COOH} = \frac{0.113*79.06}{95.27}$

$M_{CH3COOH} = 0.094 M$

Moles of $CH_3COOH$ = $95.27* 10^{-3}* 0.094$

=0.0090 moles

Moles of $KOH = 79.06*10^{-3}*0.113$

= 0.0090 moles

The equation for the reaction can be expressed as :

$CH_3COOH$ $+$ $KOH$ -----> $CH_3COO^{-}K^+$ $+$ $H_2O$

Concentration of $CH_3COO^{-$ ion = $\frac{0.0090}{Total volume (L)}$

= $\frac{0.0090}{(95.27+79.06)} *1000$

= 0.052 M

Hydrolysis of $CH_3COO^{-$ ion:

$CH_3COO^{-$ $+$ $H_2O$ -----> $CH_3COOH$ $+$ $OH^-$

$K = \frac{K_w}{K_a} = \frac{x*x}{0.052-x}$

⇒ $\frac{10^{-14}}{1.82*10^{-5}}= \frac{x*x}{0.052-x}$

= $0.5494*10^{-9}= \frac{x*x}{0.052-x}$

As K is so less, then x appears to be a very infinitesimal small number

0.052-x ≅ x

$0.5494*10^{-9}= \frac{x^2}{0.052}$

$x^2 = 0.5494*10^{-9}*0.052$

$x^2 = 0.286*10^{-10$

$x = \sqrt{0.286*10^{-10$

$x =0.535*10^{-5}M$

$[OH] = x =0.535*10^{-5}$

$pOH = -log[OH^-]$

$pOH = -log[0.535*10^{-5}]$

$pOH = 5.27$

pH = 14 - pOH

pH = 14 - 5.27

pH = 8.73

Hence, the pH of the titration mixture = 8.73

8 0

3 years ago

In 1665 Sir Isaac Newton proposed the fundamental law of gravitation as a universal force of attraction between any two bodies.

natka813 [3]

B. They are the same force. Each body acts on the other. The moon and the earth, and the apple and the earth.

8 0

3 years ago

Read 2 more answers

Balance each of the following examples of heterogeneous equilibria and write each Kc expression. Then calculate the value of Kc

wolverine [178]

Answer:

(1) 2Al(s) + 2NaOH(aq) + 6H2O(l) ↔2Na[Al(OH)4](aq) + 3H2(g)

∴ Kc = ( PH2³ * [Na[Al(OH)4]² ) / [NaOH]² = 11

(2) H2O(l) + SO3(g) ↔ H2SO4(aq)

∴ Kc = [ H2SO4 ] / PSO3 = 0.0123

(3) 2P4(s) + 6O2(g) ↔ 2P4O6(s)

∴ Kc = Kc = 1 / PO2∧6

Explanation:

(1) 2Al(s) + 2NaOH(aq) + 6H2O(l) ↔ 2Na[Al(OH)4](aq) + 3H2(g)

∴ O / Al: 0 → +2 ≡ 2e-

Na: +1 → +2

∴ R / H: +1 → 0

2 - Al - 2

2 - Na - 1

8 - O - 8

14 - H - 14

⇒ Kc = ( PH2³ * [Na[Al(OH)4]² ) / [NaOH]² = 11

(2) H2O(l) + SO3(g) ↔ H2SO4(aq)

1 - S - 1

4 - O - 4

2 - H - 2

⇒ Kc = [ H2SO4 ] / PSO3 = 0.0123

(3) 2P4(s) + 6O2(g) ↔ 2P4O6(s)

8 - P - 8

12 - O - 12

⇒ Kc = 1 / PO2∧6

6 0

3 years ago