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STALIN [3.7K]
3 years ago
12

A 50 g piece of aluminum is heated to 800c and then dropped into cold water, where the metal's temperature drops to 300c.how man

y calories does it lose to water? (specific heat capacity of aluminum is .21 cal/g0c)
Chemistry
1 answer:
Dmitry [639]3 years ago
6 0
Q = mCΔT
Q is heat, m is mass, C is specific heat, and ΔT is change in temp

Q = (50g)(.21)(500 degrees) = 5250 calories


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Otra manera para llamar la aceleración negativa es_______
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Answer:

creo que es cinemática, eso creo

8 0
2 years ago
What is the pressure of nitrogen in atmospheres of a sample that is at 745 mmHg?
Semenov [28]
<span>The pressure of nitrogen in atmospheres of a sample that is at 745 mmHg- n2= .780 atm because 78 (from the 78%) 78/100=0.78.</span>
6 0
3 years ago
A gas occupies 100 mL at 150. kPa. Find its volume at 200. kPa. You must show all your work to receive credit. Be sure to identi
PtichkaEL [24]

The Boyle-Mariotte's law or Boyle's law is one of the laws of gases that <u>relates the volume (V) and pressure (P) of a certain amount of gas maintained at constant temperature</u>, as follows:

PV = k

where k is a constant.

We can relate the state of a gas at a specific pressure and volume to another state in which the same gas is at different P and V since the product of both variables is equal to a constant, according to the Boyle's law, which will be the same regardless of the state of the gas. In this way,

P₁V₁ = P₂V₂

Where P₁ and V₁ is the pressure and volume of the gas to a state 1 and P₂ and V₂ is the pressure and volume of the same gas in a state 2.

In this case, in the state 1 the gas occupies a volume V₁ = 100 mL at a pressure of P₁ = 150 kPa. Then, in the state 2 the gas occupies a volume V₂ (that we must calculate through the boyle's law) at a pressure of P₂ = 200 kPa.  Substituting these values in the previous equation and clearing V₂, we have,

P₁V₁ = P₂V₂ → V₂ = \frac{P1V1}{P2}  

→ V₂ = \frac{100 mL x 150 kPa}{200 kPa}

→ V₂ = 75 mL

Then, the volume occupied by the gas at 200 kPa is V₂ = 75 mL

6 0
3 years ago
The heat of fusion for a substance is 122 joules per gram. How many joules of heat are need to melt 7.50 grams of this substance
daser333 [38]
<h3>Answer:</h3>

915 Joules

<h3>Explanation:</h3>
  • The heat of fusion is the heat that is required to convert a given mass of a substance from solid state to liquid state without change in temperature.
  • In this case, we are given specific heat of a substance as 122 joules per gram
  • It means that amount of heat equivalent to 122 joules is required to change 1 gram of the substance from solid state to liquid state.
  • Therefore, we can determine the amount of heat needed to change 7.5 grams of the substance from solid to liquid state.

1 g = 122 Joules

7.5 g = ?

       = 122 × 7.5

      = 915 Joules

Thus, 7.5 g of the substance at its melting point will require 915 Joules of heat to melt.

4 0
3 years ago
A certain atom has an atomic number of four. how many protons does it have? 8 2 0 4 description
Contact [7]
4 protons the number of proton has the same number of electron [which is the same as atomic number]
4 0
3 years ago
Read 2 more answers
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