Write the quadratic equation in standard form: 2x – 1=-x^2

Mathematics

1 answer:

klasskru [66]3 years ago

3 0

Answer: -x^2-2x-1

Step-by-step explanation:

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Hurry !!!! I need help

Anna [14]

Answer:

x = 66

Step-by-step explanation:

m<5 + m<6 = 180

2x + 48 = 180

2x = 132

x = 66

4 0

3 years ago

Solve the system of equations by substitution

r-ruslan [8.4K]

We have y=2x and y=x+2
They both equal y, so substitute the first equation for y in the second equation.
2x=x+2
Let’s get x to one side. Let’s subtract x from both sides.
X=2
Since x=2, just plug in 2 for x.
2+2=4
So,
X=2
Y=4

6 0

3 years ago

Which is the interval notation represent the domain?

Kazeer [188]

Answer:

The first choice, $(-\infty, 7) \cup (7, \infty)$ .

Step-by-step explanation:

The dashed vertical line is a vertical asymptote. The x-coordinate of all points on this vertical asymptote are equal to 7. In other words, when the x-value of a point on the graph approaches $7$ , its y-value approaches infinity (or negative infinity.)

Either way, the graph is not defined for $x = 7$ . The point $7$ should thus be excluded from the domain of the graph.

The graph is apparently defined for all other x-values. The domain of the function should thus be all real numbers with the exception of $x = 7$ . Here's how to write that in interval notation:

The set of all real numbers can be expressed as the interval $(-\infty, \infty)$ . Note that infinity $\infty$ (or $(- \infty)$ itself isn't a real number. The round brackets indicate that both endpoints are excluded from the from the interval.
The set of all real numbers less than (not equal to) $7$ is $(-\infty,7 )$ (both ends are excluded.) The set of all real numbers greater than (not equal to) $7$ is $(7, \infty)$ .
The set of all real numbers that is not equal to $7$ is the union of all real numbers less than $7$ and all real numbers greater than $7$ . The union operator $\cup$ connects two intervals.