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2 years ago

_____ bonds are formed when the electronegativity difference is 0.4 > 2.0. Give two examples:

1 answer:

34kurt2 years ago

6 0

Ionic Bond is formed when the electronegativity difference is 0.4 > 2.0. Electronegativity is a term that can be defined as a tendency of an atom to attract electron towards its own self.

Explanation:

Electronegativity is a term that can be defined as a tendency of an atom to attract electron towards its own self.

An electronegativity of an atom is affected by

The atomic number of the atom
Secondly by the distance at which the valence electron are residing from the nucleus

1. In case the electronegativity difference (which is denoted by ΔEN) is less than 0.5 then the bond formed is known as Nonpolar covalent.

2. In case the ΔEN is in between 0.5 and 1.6, the bond formed is referred to as the Polar covalent

3. In case the ΔEN is more /greater than 2.0, then the bond formed is referred to as Ionic Bond

2 Examples of Ionic bonds

The formation of sodium fluoride, NaF, from a sodium atom and a fluorine atom is an example of Ionic bond formation.
Another example is the formation of NaCl from sodium (Na),which is a metal, and chloride (Cl), which is a nonmetal

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The pressure on a 200 milliliter sample of CO2 (g) at constant temperature is increased from

balu736 [363]

The answer for the following problem is mentioned below.

Therefore the final volume of the gas is 100 ml.

Explanation:

Given:

Initial pressure ( $P_{1}$ ) = 600 mm of Hg

Final pressure ( $P_{2}$ ) = 1200 mm of Hg

Initial volume ( $V_{1}$ ) = 200 ml

To find:

Final volume ( $V_{2}$ )

We know;

According to the ideal gas equation,

P × V = n × R × T

Where;

P represents the pressure of the gas

V represents the volume of the gas

n represents the no of moles of the gas

R represents the universal gas constant

T represents the temperature of the gas

So,

From the above mentioned equation,

P × V = constant

$\frac{P_{1} }{P_{2} }$ = $\frac{V_{1} }{V_{2} }$

Where,

( $P_{1}$ ) represents the initial pressure of the gas

( $P_{2}$ ) represents the final pressure of the gas

( $V_{1}$ ) represents the initial volume of the gas

( $V_{2}$ ) represents the final volume of the gas

So;

$\frac{600}{1200}$ = $\frac{V_{2} }{200}$

$V_{2}$ = 100 ml

Therefore the final volume of the gas is 100 ml.

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3 years ago

Weight of one mole of carbon = 12.01 g Weight of one mole of oxygen = 16.00 g The molecular weight (gram formula weight) for CO

murzikaleks [220]

Answer:

28.01g

Explanation:

Given the weight of one mole of Cabon as 12.01g and that of oxygen as 16.00g.

The molecular weight of a compound can be gotten by adding the molar weights of the elements that constitutes the compound .

The molecular weight of the compound CO is therefore

equal to the sum of the weight of both elements.

That’s = 12.01g + 16.00g

= 28.01g

Therefore, the molecular weight of CO is 28.01g

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Answer:

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