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stealth61 [152]
3 years ago
15

_____ bonds are formed when the electronegativity difference is 0.4 > 2.0. Give two examples:

Chemistry
1 answer:
34kurt3 years ago
6 0

<u>Ionic Bond</u> is formed when the electronegativity difference is 0.4 > 2.0. Electronegativity is a term that can be defined as a tendency of an atom to attract electron towards its own self.

Explanation:

Electronegativity is a term that can be defined as a tendency of an atom to attract electron towards its own self.

An  electronegativity of an atom is affected by

  • The atomic number of the atom
  • Secondly by the distance at which the valence electron are residing from the nucleus

1. In case the  electronegativity difference (which is denoted by  ΔEN) is less than 0.5  then the bond formed is known as N<u>onpolar covalent. </u>

2. In case  the ΔEN is in between 0.5 and 1.6, the bond formed is referred to as the<u> Polar covalent </u>

3. In case  the ΔEN is more /greater  than 2.0, then the bond formed is referred to as<u> Ionic Bond</u>

<u>2 Examples of Ionic bonds</u>

  • The formation of sodium fluoride, NaF, from a sodium atom and a fluorine atom is an example of Ionic bond formation.
  • Another example is the formation of NaCl from  sodium (Na),which is  a metal, and chloride (Cl), which is a  nonmetal

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Calculate the cfse for a d^3 system in an octahedral field in units of ∆_o. In other words, do not enter "∆_o" with your answer.
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Magnetic moment (spin only) of octahedral complex having CFSE=−0.8Δo and surrounded by weak field ligands can be : Q

To answer this, the Crystal Field Stabilization Energy has to be calculated for a (d3 metal in both configurations. The geometry with the greater stabilization will be the preferred geometry. So for tetrahedral d3, the Crystal Field Stabilization Energy is: CFSE = -0.8 x 4/9 Δo = -0.355 Δo.

[Co(CN)64-] is also an octahedral d7 complex but it contains CN-, a strong field ligand. Its orbital occupancy is (t2g)6(eg)1 and it therefore has one unpaired electron. In this case the CFSE is −(6)(25)ΔO+(1)(35)ΔO+P=−95ΔO+P.

The crystal field stabilization energy (CFSE) (in kJ/mol) for complex, [Ti(H2O)6]3+. According to CFT, the first absorption maximum is obtained at 20,3000cm−1 for the transition.

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8 0
1 year ago
Fe2O3(s) + 3H2(g) → 2Fe(s) + 3H2O(1)<br> How many moles of iron can be made from 3 moles of Fe2O3?
enot [183]

<em>ANSWER - 6 MOLES OF </em><em>IRON</em>

Fe2O3(s) + 3H2(g) → 2Fe(s) + 3H2O(1)

One moles of Fe2O3 forming 2 moles of Fe

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FrozenT [24]

The answer is: volume of nitrogen is 70L.

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m(N₂H₄) = 100 g; mass of hydrazine.

M(N₂H₄) = 32 g/mol; molar mass of hydrazine.

n(N₂H₄) = m(N₂H₄) ÷ M(N₂H₄).

n(N₂H₄) = 100 g ÷ 32 g/mol.

n(N₂H₄) = 3.125 mol; amount of hydrazine.

m(O₂) = 100 g; mass of oxygen.

M(O₂) = 32 g/mol; molar mass of oxygen.

n(O₂) = 100 g ÷ 32 g/mol.

n(O₂) = 3.125 mol; amount of oxygen.

From chemical reaction: n(O₂) : n(N₂) = 1 : 1; n(O₂) = n(N₂).

n(N₂) = 3.125 mol; amount og nitrogen gas.

V(N₂) = n(N₂) · Vm.

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V(N₂) = 3.125 mol · 22.4 L/mol.

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Answer:

Neutral subatomic particle that is a constituent of every atomic nucleus except ordinary hydrogen.

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