I've attached the complete question.
Answer:
Only participant 1 is not cheating while the rest are cheating.
Because only participant 1 has a z-score that falls within the 95% confidence interval.
Step-by-step explanation:
We are given;
Mean; μ = 3.3
Standard deviation; s = 1
Participant 1: X = 4
Participant 2: X = 6
Participant 3: X = 7
Participant 4: X = 0
Z - score for participant 1:
z = (x - μ)/s
z = (4 - 3.3)/1
z = 0.7
Z-score for participant 2;
z = (6 - 3.3)/1
z = 2.7
Z-score for participant 3;
z = (7 - 3.3)/1
z = 3.7
Z-score for participant 4;
z = (0 - 3.3)/1
z = -3.3
Now from tables, the z-score value for confidence interval of 95% is between -1.96 and 1.96
Now, from all the participants z-score only participant 1 has a z-score that falls within the 95% confidence interval.
Thus, only participant 1 is not cheating while the rest are cheating.
Answer:
p ( x > 2746 ) = p ( z > - 1.4552 )
= 1 - 0.072806
= 0.9272
This shows that there is > 92% of a republican candidate winning the election hence I will advice Gallup to declare the Republican candidate winner
Step-by-step explanation:
Given data:
51% of male voters preferred a Republican candidate
sample size = 5490
To win the vote one needs ≈ 2746 votes
In order to advice Gallup appropriately lets consider this as a binomial distribution
n = 5490
p = 0.51
q = 1 - 0.51 = 0.49
Hence
> 5 while
< 5
we will consider it as a normal distribution
From the question :
number of male voters who prefer republican candidate ( mean ) ( u )
= 0.51 * 5490 = 2799.9
std =
=
= 37.0399 ---- ( 1 )
determine the Z-score = (x - u ) / std ---- ( 2 )
x = 2746 , u = 2799.9 , std = 37.0399
hence Z - score = - 1.4552
hence
p ( x > 2746 ) = p ( z > - 1.4552 )
= 1 - 0.072806
= 0.9272
This shows that there is > 92% of a republican candidate winning the election hence I will advice Gallup to declare the Republican candidate winner
Answer:
n=3.8416≅4
So Minimum Sample Size is 4
Step-by-step explanation:
In order to find the minimum sample size, the formula we use will be:
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Where:
n is sample size
Z is the distribution
S is the standard deviation
E is the Margin of error
S=3 ,E=3
For Z:
Alpha=1-0.95=0.05
Alpha/2=0.025=2.5%
From Cumulative Standard Distribution Table:
Z at Alpha/2 = 1.960

n=3.8416≅4
So Minimum Sample Size is 4
Answer:
10
Step-by-step explanation:
Given that:
Company A:
40 defective out of every 5000
Company B :
30 out of every 6000
To obtain the highest number of defective phones both companies can produce in common :
Factors of :
40 : 2, 4, 5, 8, 10, 20, 40
30 : 2, 3, 5, 6, 10, 15, 30
Hence, highest number of defective phones both companies can produce in common is 10