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Svet_ta [14]
4 years ago
9

A teacher randomly selects three students each month from a class of 30 students to be the students of the month. Each student r

eceives a
special certificate special seating in class, and a free homework pass. How many different groups of three students could be selected?
​
Mathematics
1 answer:
Lunna [17]4 years ago
4 0

Answer:

10 groups

Step-by-step explanation:

because 30 divided by 3 is 10

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1/2n+3=6 what is the solution to this equation
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Answer:

n=6

Step-by-step explanation:

1/2 n + 3 = 6

Subtract 3 from each side

1/2 n +3-3=6-3

1/2n = 3

Multiply each side by 2

1/2 n * 2 = 3*2

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5) Find the area of a rectangle<br> with points at (-8,5), (2,5),<br> (2,-3) and (-8,-3).
Lady bird [3.3K]

Answer:

80 units²

Step-by-step explanation:

Given <u>vertices</u> of a rectangle:

  • A = (-8, 5)
  • B = (2, 5)
  • C = (2, -3)
  • D = (-8, -3)

As points A and D share the <u>same x-coordinate</u>, and points B and C share the <u>same x-coordinate</u>, the difference between the different <u>x-coordinates</u> is the length of the rectangle:

\begin{aligned}\implies \textsf{Length} & = x_B-x_A\\& = 2-(-8)\\& = 2+8\\& = 10\; \sf units\end{aligned}

As points A and B share the <u>same y-coordinate</u>, and points C and D share the <u>same y-coordinate</u>, the difference between the different <u>y-coordinates</u> is the width of the rectangle:

\begin{aligned}\implies \textsf{Width} & = y_A-y_D\\& = 5-(-3)\\& = 5+3\\& = 8\; \sf units\end{aligned}

Therefore:

\begin{aligned}\textsf{Area of a rectangle} & = \sf width \times length\\&=8 \times 10\\&=80 \sf \; units^2\end{aligned}

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2 years ago
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gulaghasi [49]

Answer:

a. x=7  b. x= 4.5   c. c= 3

Step-by-step explanation:

a. 5x=35

   5x/5=35/5

     x = 7

b. 4x=18

    4x/4=18/4

     x=4.5

c. 6c-2c=12

   4c = 12

   4c/4 = 12/4

     c=3

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3 years ago
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