Answer:
change in kinetic energy of the trolley is 53.91 J.
Explanation:
mass of the trolley, m = 5.0 kg
initial velocity of the trolley, u = 1.0 m/s
external force on the trolley, F = 25 N
time of force action, t = 0.75 s
The final velocity of the trolley at the end of 0.75 s is calculated as follows;
The change in kinetic energy of the trolley is calculated as;
Δ K.E = ¹/₂m(v² - u²)
Δ K.E = ¹/₂ x 5(4.75² - 1²)
Δ K.E = 53.91 J.
Therefore, change in kinetic energy of the trolley is 53.91 J.
Answer:
Electric field will remain same.
Explanation:
Given that
At initial condition ,charge q = +3μ C
Electric field E = 4106 N/c
As we know that
Electric field due to charge q
Now when charge is replaced by new charge q'= -3μ C
From the expression of electric field we can say that electric field will remain same from same quantity of electric charge.
So we can say that electric field will remain same.
Answer:
a)this graph is also a line b) in both cases we have a uniform movement
Explanation:
In this exercise we have a uniform movement
v = d / t
d = v t
in the table we give some values to make the graph
t (s) d (m)
1 10
2 20
3 30
In the attached we can see the graph that is a straight line
we have another vehicle at v = 50 me / S
t (s) d (m)
1 50
2 100
3 150
this graph is also a line
b) in both cases we have a uniform movement
