A test charge of +3 µC is at a point P where the electric field due to the other charges is directed to the right and has a magn
1 answer:
Answer:
Electric field will remain same.
Explanation:
Given that
At initial condition ,charge q = +3μ C
Electric field E = 4106 N/c
As we know that
Electric field due to charge q
Now when charge is replaced by new charge q'= -3μ C
From the expression of electric field we can say that electric field will remain same from same quantity of electric charge.
So we can say that electric field will remain same.
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Answer:
The wavelength of the wave is 20 m.
Explanation:
Given that,
Amplitude = 10 cm
Radial frequency
Bulk modulus = 40 MPa
Density = 1000 kg/m³
We need to calculate the velocity of the wave in the medium
Using formula of velocity
Put the value into the formula
We need to calculate the wavelength
Using formula of wavelength
Put the value into the formula
Hence, The wavelength of the wave is 20 m.
Answer:
a.
b.
c.
Explanation:
First, look at the picture to understand the problem before to solve it.
a. d1 = 1.1 mm
Here, the point is located inside the cilinder, just between the wire and the inner layer of the conductor. Therefore, we only consider the wire's current to calculate the magnetic field as follows:
To solve the equations we have to convert all units to those of the international system. (mm→m)
μ0 is the constant of proportionality
μ0=4πX10^-7 N*s2/c^2
b. d2=3.6 mm
Here, the point is located in the surface of the cilinder. Therefore, we have to consider the current density of the conductor to calculate the magnetic field as follows:
J: current density
c: outer radius
b: inner radius
The cilinder's current is negative, as it goes on opposite direction than the wire's current.
c. d3=7.4 mm
Here, the point is located out of the cilinder. Therefore, we have to consider both, the conductor's current and the wire's current as follows:
As we see, the magnitud of the magnetic field is greater inside the conductor, because of the density of current and the material's nature.
