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olga2289 [7]
4 years ago
10

1. Take the speed at which the body moves as 10 m/s 2. Calculate the distance travelled by the body every second 3. Take the tim

e on the x-axis and distance travelled on the y-axis 4. Plot the distance vs time graph on a centimeter graph sheet taking 1cm= 1 s 5. Repeat the steps 2-4 for a speed of 50 m/s on the same graph sheet 6. Observe the graphs obtained for different speeds a) Find the nature of the graph obtained b) What kind of motion is obtained- uniform/non-uniform?

Physics
1 answer:
exis [7]4 years ago
3 0

Answer:

a)this graph is also a line     b) in both cases we have a uniform movement

Explanation:

In this exercise we have a uniform movement

     v = d / t

     d = v t

in the table we give some values ​​to make the graph

       t (s)    d (m)

        1         10

        2        20

        3         30

In the attached we can see the graph that is a straight line

we have another vehicle at v = 50 me / S

t (s)     d (m)

1         50

2        100

3         150

this graph is also a line

b) in both cases we have a uniform movement

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Will give brainlist.
Lera25 [3.4K]

Answer:

<u>Displacement (km)</u>

Explanation:

The y axis is the vertical axis pointing up and down. This is labeled as the the displacement (km) in the graph.

6 0
3 years ago
Can 200 watts lift a 100 kg box,and if so how long would it take?
topjm [15]
The only definite number we can tell you is that in order to lift
a 100kg box, you have to somehow provide a force of about
980 newtons (about 220 pounds) pointing upward.  That's the
weight of the box, and you have to lift with at least that much force
just to get the box off the ground.

After that, the answer to your question is 'YES'.  The time it takes
depends on how much force you have available, how far you want
to lift the box, and how fast.

Here are the Physics formulas you have to use:

-- The amount of "Work" you'll do is

    (the amount of force you use) times (how far up you lift the box) .

-- The "Power" (amount of watts) you'll use is

    (the amount of 'work' you do) divided by (the length of time it takes).  

So ...

-- The higher you lift the box, the more 'work' your lift-machine does.

-- The faster the box is lifted, the more 'power' your lift-machine needs.
4 0
3 years ago
When area increases, pressure decreases. Find two situations where this principle is applied.
BigorU [14]

Answer:

Explanation:

Pressure can be defined as the force per unit area hence there is an inverse relationship between pressure exerted by a substance and the area of that substance. For instance,

(1) if a bag of sand if filled with sand and an individual steps on this bag. The feet of he individual will form no shape/displace little sand sideways in the bag. But if the same quantity of sand is poured in a bigger bag (larger area) and the same individual stands on the bag, the feet of the individual will "sink" (decreased pressure from the bag) displacing some sand sideways.

(2) The straps of a bag are made wide (and not slim) so that the bag can exert lesser pressure on the shoulders when the same quantity of load is carried by the bag than if the straps were made narrow/slim.

5 0
3 years ago
The height of the Empire State Building is 318.00 meters. If a stone is dropped from the top of the building, what is the stone'
jonny [76]
D = 318 meters
vi = 0 m/s
vf =????
a = 9.81

Formula
=======
vf^2 = vi^2 + 2*a*d

Substitute and solve.
================
vf^2 = 0^2  + 2 * 9.81 * 318
vf^2 = 6239.16
v = sqrt(6239.16)
v = 78.990 m/s I guess down is minus in your classroom.
Anyway pick -79 <<<<<=======
7 0
3 years ago
A lightning bolt may carry a current of 1.00 104 A for a short time. What is the resulting magnetic field 160 m from the bolt? S
ZanzabumX [31]

Answer:

Result magnetic field=

1.25*10^-^5T

Explanation:

We are given:

I = 1.00*10^4A

r = 160m

Let us say the lightning bolt is a long straight conductor.

Therefore we will use the formula:

B = Uo•I / 2πr

Substituting figures in the equation, we have:

B = [(4π*10^-^7 T•m/A)(1.00*10^4)] / (2π * 160);

= 1.25 * 10^-^5 T;

Therefore, the result magnetic field at 160m = 1.25 * 10^-^5

4 0
3 years ago
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