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zheka24 [161]
3 years ago
13

A 0.20 kg mass is oscillating at a small angle from a light string with a period of 0.78 s.

Physics
2 answers:
Scorpion4ik [409]3 years ago
7 0

Answer:

L = 15 cm

Explanation:

T = 2π√(L/g)

L = g(T/2π)²

L = 9.8(0.78/2π)²

L = 0.151027... m

L = 15 cm

navik [9.2K]3 years ago
3 0

Answer: .15m

Explanation:

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elena55 [62]

The correct answer D: all of the above

5 0
3 years ago
PLZZZZ HELPPPPPPP MEHHHHHHHH ASAP!!! 20 POINTS!!<br> I am desperate.... <br> :'(
Katarina [22]

Answer:

i think it is d

Explanation:

8 0
3 years ago
The pressure at the bottom of a cylindrical container with a cross-sectional area of 45.5 cm2 and holding a fluid of density 420
iris [78.8K]

Answer:

3.33 m

Explanation:

Pressure is the distributed force applied to the surface of an object per unit area. The force is applied perpendicular to the surface of the object. The SI unit of pressure is N/m² or Pa.

Hydrostatic pressure is the pressure that a fluid exerts at a point due to the force of gravity.

The relationship between  pressure on the bottom of the container,  atmospheric pressure and the pressure due to the depth of the fluid is given by:

P_{bottom}-P_{atm}=P_{depth}\\\\where\ P_{bottom}=pressure\ at\ the \ fluid\ bottom,\ P_{atm}=atmospheric\ pressure\\P_{depth}=pressure\ due\ to\ fluid\ depth=\rho gh. \ Hence:\\\\P_{bottom}-P_{atm}=\rho gh\\\\Given \ that\ P_{bottom}=115\ kPa=115*10^3\ Pa, let\ us\ assume\ P_{atm}=101\ kPa=101*10^3\ Pa,\rho=420\ kg/m^3,g=acceleration\ due\ to \ gravity=10\ m/s^2.\\\\Therefore:\\\\115*10^3-101*10^3=420*10*h\\\\14*10^3=4200h\\\\h=3.33\ m\\\\

6 0
3 years ago
Which type of food additive should Maria add to increase the consistency of the batter? Maria wants to improve the consistency o
arsen [322]

Cornstarch is a thickening agent

6 0
3 years ago
You are playing ice hockey with friends on a frozen pond. The hockey puck (mass 0.2 kg) is sliding on the ice at 10 m/s when it
chubhunter [2.5K]

Answer:

The mass of the hailstone is  m_2 = 0.05

Explanation:

From the question we are told that

    The mass of the hockey puck is m_1  = 0.2 \ kg

     The initial speed of the puck is u_1 =  10 \ m/s

      The final speed of the puck is  v_f  =  8 \ m/s

According to the principles of linear momentum

      m_1u_1 + m_2u_2 = (m_1 + m_2)v_f

At initial the velocity of the hailstone was zero so

       u_2 =  0 \ m/s

So  

     m_1 u_1 =  (m_1 + m_2 )v_f

substituting values

        0.2 *  10 =  (0.2 + m_2 )* 8

=>     2 =  (0.2 + m_2 )* 8

=>     0.25 = 0.2 + m_2

=>    m_2 = 0.05

6 0
3 years ago
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