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ale4655 [162]
2 years ago
13

Can a golf ball bounce like a rubber ball? Due in 1 hour. 15 points.

Physics
1 answer:
klasskru [66]2 years ago
5 0

Answer:

So, I tested it out and came to a conclusion.

The rubber ball is quite bouncy due to the fact that it is made of rubber which is what makes it bounce back and high, but although the golfball does in fact bounce back it does not bounce as high as the rubber ball due to the fact that it is made of plastic.

Explanation:

Hope this helps you out!

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Which of the following equations describes Newton’s second law
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Newton’s Second Law is F=ma (force is equal to the mass multiplied by acceleration), however, the equation can be rearranged to isolate and calculate mass from force over acceleration. Therefore, m=F/a
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While passing through a human cell, an x-ray photon interacts with and inactivates the cell’s master molecule. What is the conse
Yuliya22 [10]

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Cell Death

Explanation:

Cell death is defined as the biological process which ceases the function of the cell to carry out. This can be caused due to the formation of new cells in place of old cells.

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And another case is that when X-ray photon interact with the human cell while it passes through the cell, it   will damage the cell and cease it to function well and a more drastic condition occurs and that cell become dead.  

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2 years ago
Future passive of( win)​
Inessa05 [86]

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three point charge positioned one x-axis if the charge and corresponding positions are +32Mc x=0 +20Mc x=40cm - 60Mc x=60cm find force 32Mc

Explanation:

7 0
2 years ago
?/1 Jorge traveled 5 miles north to school. He then traveled 3 miles west to the store. Then he left the store and traveled 5 mi
aleksklad [387]

Answer:

He's 3 miles west of school.

Explanation:

He went 5 miles up and 5 miles down which means that he really didn't go up or down.  In between that, he went 3 miles west so if the 5 milers don't count, this puts him at 3 miles west of school.

4 0
2 years ago
An electron moves with a speed of 8.0×106m/s along the -z-axis. It enters a region where there is a uniform magnetic field B = (
Crazy boy [7]

Answer:

Acceleration, a=9.36\times 10^{18}\ m/s^2

Explanation:

It is given that,

Speed of electron, v=8\times 10^6\ m/s

Charge on an electron, q=1.6\times 10^{-19}\ C

Mass of electron, m=9.1\times 10^{-31}\ kg

Magnetic field, B=5.5i-3.7j

Magnitude, |B|=\sqrt{5.5^2+(-3.77)^2}=6.66\ T

Magnetic force is given by :

F=qvB

Also, F = ma

a=\dfrac{qvB}{m}

a=\dfrac{1.6\times 10^{-19}\times 8\times 10^6\times 6.66}{9.1\times 10^{-31}}

a=9.36\times 10^{18}\ m/s^2

So, the acceleration of the electron is 9.36\times 10^{18}\ m/s^2. Hence, this is the required solution.

5 0
3 years ago
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