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3 years ago

A girl is whirling a ball on a string around her head in

Physics

1 answer:

Thepotemich [5.8K]3 years ago

8 0

Answer:

Answered

Explanation:

The girl whirling the ball should let go off ball when the ball is at a position such that tangent to the circle is in the direction of the target.

the tangent at any point in a circular path indicates the direction of velocity at that point. And the moment when the centripetal force is removed the ball will follow the tangential path at that moment.

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You need to design a 60.0-Hz ac generator that has a maximum emf of 5200 V. The generator is to contain a 130-turn coil that has

dimaraw [331]

Answer:

B = 0.129 T

Explanation:

Given,

frequency, f = 60 Hz

maximum emf = 5200 V

Number of turns, N = 130

Area per turn = 0.82 m²

We know,

ω = 2 π f

ω = 2 π x 60 = 376.99 rad/s

now, Magnetic field calculation

$B =\dfrac{\epsilon_{max}}{NA\omega}$

$B =\dfrac{5200}{130\times 0.82\times 376.99}$

B = 0.129 T

Hence, the magnetic field is equal to B = 0.129 T

3 0

3 years ago

As stars age and become larger they become ________ and ________

sleet_krkn [62]

They become old and explode.

5 0

3 years ago

Please Help Me

JulijaS [17]

1. a=Δv/Δt=(v-vo)/t=(0-25)/5=-25/5=-5 m/s²

The "-" sign shows us that the car has a slow motion

2.a=Δv/Δt=(v-vo)/t=(10-0)/4=10/4=2,5 m/s²

3.they do not have acceleration because they go at constant speed

7 0

3 years ago

A 1200N load is to be lifted with 200N effort using a first class lever. At what distance

kipiarov [429]

Explanation:

Hey there!!

Let's simply work with it.

Here,

load = 1200N

Effort = 200N

Load distance = 15cm

We have,

According to the principle of lever.

L×LD = E×ED.

1200×15 = 200× ED.

18000 = 200ED.

$ed = \frac{18000}{200}$

Therefore, Effort Distance = 90cm.

Hope it helps....

7 0

3 years ago

A 0.25 kg arrow with a velocity of 12 m/s to the west strikes and pierces the center of a 6.8 kg target. What is the final veloc

Mademuasel [1]

Answer:20/47 meter per second

Explanation:

Mass of arrow(ma)=0.25kg

Velocity of arrow(va)=12m/s

Mass of target(mt)=6.8kg

Velocity of target(vt)=0 since target is at rest

Conservation of linear momentum says that :

maxva+mtxvt=(ma+mt)V

V=(maxva+mtxvt)/(ma+mt)

V=(0.25x12+6.8x0)/(0.25+6.8)

V=3/(7.05)

V=20/47 meter per second

4 0

3 years ago