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Dahasolnce [82]
3 years ago
15

A 1.15 kg book is at rest on the table. What is the magnitude of the normal force that the table is exerting on the book?

Physics
1 answer:
Agata [3.3K]3 years ago
5 0

Answer:

11.27N

Explanation:

Given parameters:

Mass of the book  = 1.15kg

Unknown:

Magnitude of the normal force  = ?

Solution:

The normal force is the vertical force exerted by a body on an object.

It can be described as the weight of an object.

 Normal force  = mass x acceleration due to gravity

 Normal force  = 1.15 x 9.8  = 11.27N

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Jeremy walked at an average rate of speed of 5 km/h. how far had Jeremy walked in 15 minutes?
astraxan [27]

Answer:

1 half kilometer is right answer

5 0
3 years ago
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How to calculate the average velocity, in m/s.
saw5 [17]
Using the average velocity formula which is total distance divided by total time. If the distance is given in km convert to m then divide by 1000 to get m and if time is given in minutes then divide by 60 to get seconds. And after converting, divide to get your final answer in m/s. Hope that helped!
4 0
3 years ago
A 600 kg car is at rest, and then accelerates to 5 m/s.
Crank

Answer:

0

7500J

7500J

Explanation:

Given parameters:

Mass of car  = 600kg

Velocity  = 5m/s

Unknown:

Original kinetic energy  = ?

Final kinetic energy  = ?

Work used  = ?

Solution:

The kinetic energy of a body is the energy due to the motion of a body.

It can be solve mathematically using expression below;

                K.E  = \frac{1}{2}  m v²

  where m is mass

              v is velocity

original kinetic energy;

  The car started at rest and v = 0, therefore K.E  = 0

Final kinetic energy;

           K.E  = \frac{1}{2}  x 600 x 5²   = 7500J

Work done:

   Work done  = Final K.E  - Initial K.E  = 7500 - 0 = 7500J

   

3 0
3 years ago
4. What distance will a truck travel in 3 hours at an average speed of 50 miles per hour?
Alja [10]

Answer:

150 miles

Explanation:

just do 50x3

3 0
2 years ago
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Crew members attempt to escape from a damaged submarine 141 m below the surface.What force must be applied to a pop-out hatch, w
AfilCa [17]

Answer:

20.9 x 10⁵ N

Explanation:

The external air pressure downwards and internal air pressure upwards will cancel out. TH net pressure to be faced will be due to water column of 141 m depth.

Pressure of water = hdg = 141 x 1024 x 9.8 = 14.15 x 10⁵ Pa

Area of hatch = 1.72 x 0.859 = 1.4775 sq m.

Total force required = area x pressure = 14.15 x 10⁵ x 1.4775 = 20.9 x 10⁵ N.

3 0
3 years ago
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