In order to answer this, we would need to know
the half-life of ⁴⁰K. Perhaps when you look that up,
you'll be able to answer this on your own.
Acceleration is the change of velocity, and velocity is the change of distance. The opposite of finding change, or differentiation, is integration.
Acceleration = 1.3 m/s²
Velocity: ∫ 1.3 dx = 1.3x + c m/s
Distance: ∫ 1.3x dx = 1.3x²/2 + c m
Distance run: 1.3*3²/2 = 5.85 m
<em>What</em><em> </em><em>bad</em><em> </em><em>thing</em><em> </em><em>happened</em><em>?</em>
The new rotational speed of the combined system is 32 rad/s
<u>Explanation:</u>
Given-
Moment of Inertia, I = 8 kg m²
speed of rotation, ω = 4 rad/s
Mass of the lump = 1 kg
distance = 1 m
New rotational speed = ?
We know,
When the lump is dropped on the rotating disc then the angular momentum remains conserved.
Angular Momentum of the disc, Lₐ = Iω
Angular momentum of the lump, L ₓ = mvR
Since the angular momentum remains conserved,
Lₐ = Lₓ
8 X 4 = 1 X v X 1
New rotational speed, v = 32 rad/s
Therefore, the new rotational speed of the combined system is 32 rad/s.
Answer:
Explanation:
Given,
Length of the Pipe, L = 80 cm
Frequency ,f = ?
Speed of sound, v = 343 m/s
Wavelength when pipe is open at both the ends
Fundamental frequency
Answer:
a) r = 6.81 cm : radius of the sphere
b) A = 582.78 cm² : surface area of the sphere
c) V = 1322.91 cm³ : volume of the sphere
Explanation:
Formula to calculate the surface area of the sphere:
A = 4×π×r² Formula (1)
Formula to calculate the volume of the sphere:
V = (4/3)×π×r³ Formula (2)
Problem development
a)
d = 5.36 in
1 in = 2.54 cm
r = d/2
Where:
r: sphere radius (cm)
d: sphere diameter (cm)
r = 13.614/2 = 6.81 cm
b)
We replace in formula (1)
A = 4×π×(6.81)² = 582.78 cm²
c)
We replace in formula (2)
V = (4/3)×π×(6.81)³ = 1322.91 cm³