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harina [27]
4 years ago
12

The simple pendulum above consists of a bob hanging from a light string. You wish to experimentally determine the frequency of t

he swinging pendulum. (a) By checking the line next to each appropriate item on the list below, select the equipment that you would need to do the experiment. ____ Meter Stick ____ Protractor ____ Additional string ____ Stopwatch ____ Photogate ____ Additional masses (b) Describe the experimental procedure that you would use. In your description, state the measurements you would make, how you would use the equipment to make them, and how you would determine the frequency from those measurements. (c) You next wish to discover which parameters of a pendulum affect its frequency. State one parameter that could be varied, describe how you would conduct the experiment, and indicate how you would analyze the data to show whether there is a dependence. (d) After swinging for a long time, the pendulum eventually comes to rest. Assume that the room is perfectly thermally insulated. How will the temperature of the room change while the pendulum comes to rest
Physics
1 answer:
wel4 years ago
5 0

Answer:

See explaination

Explanation:

a) We will simply need a STOPWATCH

b) Just let the pendulum to swing 10 times, record the time and then divide it by 10, we have the time period of the pendulum. Then frequency can be found as

f = 1/T

c) As per the time period equation for simple pendulum, we can change the length of pendulum easily to vary the frequency

d) The temperature of room would slightly increase because mechanical energy will convert to thermal energy

e) Period will increase because with increase in temperature, metal will expand and longer pendulum will have more period.

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A flock of ducks is trying to migrate south for the winter, but they keep being blown off course by a wind blowing from the west
Minchanka [31]

The ducks' flight path as observed by someone standing on the ground is the sum of the wind velocity and the ducks' velocity relative to the wind:

ducks (relative to wind) + wind (relative to Earth) = ducks (relative to Earth)

or equivalently,

\vec v_{D/W}+\vec v_{W/E}=\vec v_{D/E}

(see the attached graphic)

We have

  • ducks (relative to wind) = 7.0 m/s in some direction <em>θ</em> relative to the positive horizontal direction, or

\vec v_{D/W}=\left(7.0\dfrac{\rm m}{\rm s}\right)(\cos\theta\,\vec\imath+\sin\theta\,\vec\jmath)

  • wind (relative to Earth) = 5.0 m/s due East, or

\vec v_{W/E}=\left(5.0\dfrac{\rm m}{\rm s}\right)(\cos0^\circ\,\vec\imath+\sin0^\circ\,\vec\jmath)

  • ducks (relative to earth) = some speed <em>v</em> due South, or

\vec v_{D/E}=v(\cos270^\circ\,\vec\imath+\sin270^\circ\,\vec\jmath)

Then by setting components equal, we have

\left(7.0\dfrac{\rm m}{\rm s}\right)\cos\theta+5.0\dfrac{\rm m}{\rm s}=0

\left(7.0\dfrac{\rm m}{\rm s}\right)\sin\theta=-v

We only care about the direction for this question, which we get from the first equation:

\left(7.0\dfrac{\rm m}{\rm s}\right)\cos\theta=-5.0\dfrac{\rm m}{\rm s}

\cos\theta=-\dfrac57

\theta=\cos^{-1}\left(-\dfrac57\right)\text{ OR }\theta=360^\circ-\cos^{-1}\left(-\dfrac57\right)

or approximately 136º or 224º.

Only one of these directions must be correct. Choosing between them is a matter of picking the one that satisfies <em>both</em> equations. We want

\left(7.0\dfrac{\rm m}{\rm s}\right)\sin\theta=-v

which means <em>θ</em> must be between 180º and 360º (since angles in this range have negative sine).

So the ducks must fly (relative to the air) in a direction 224º relative to the positive horizontal direction, or about 44º South of West.

8 0
3 years ago
What makes gravity work
olganol [36]
Well we have two concepts of gravity now. In Newton's concept masses create forces between them. In Einstein's concept mass distorts time and space around it and makes masses move as if there are forces between them.
So whichever concept you prefer it's the presence of mass that creates gravity.
7 0
4 years ago
Liquid sodium can be used as a heat transfer fluid. Its vapor pressure is 40.0 torr at 633°C and 400.0 torr at 823°C. Calculate
kaheart [24]

Answer:

H vaporization = 100.0788 kJ/mol

Explanation:

Use clausius clapyron's adaptation for the calculation of Hvap as:

ln\frac {P_2}{P_1}=\frac {H_{vap}}{R}(\frac {1}{T_1}-\frac {1}{T_2})

Where,

P₂ and P₁ are the pressure at Temperature T₂ and T₁ respectively.

R is the gas constant.

T₂ = 823°C

T₁ = 633°C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So, the temperature,

T₂ = (823 + 273.15) K = 1096.15 K

T₁ = (633 + 273.15) K = 906.15 K

P₂ = 400.0 torr , P₁ = 40.0 torr

R = 8.314 J/K.mol

Applying in the formula to calculate heat of vaporization as:

ln \frac {400}{40}=\frac {H_{vap}}{R} (\frac {1}{906.15}-\frac {1}{1096.15})

Solving for heat of vaporization, we get:

H vaporization = 100078.823 J/mol

Also, 1 J = 10⁻³ kJ

So,

<u>H vaporization = 100.0788 kJ/mol</u>

4 0
3 years ago
Need help with this science!!
noname [10]
Lol, I remember I helped my sister with this question but anyways, the card flew because of inertia and the quarter fell in the glass because of gravity :).
3 0
3 years ago
A rectangular object was found to have a mass of 1.278 kg and density of 4.98  g/cm3. Suppose that you knew that the length was
Leni [432]

Answer:

89.6 cm

Explanation:

From the question,

Volume of the rectangular object = Mass/Density.

V = m/D.................. Equation 1

Given: m = 1.278 kg, D = 4.98 g/cm³ = 4980 kg/m³

Substitute into equation 1

V = 1.278/4980

V = 2.57×10⁻⁴ m³.

But,

V = lwh............... Equation 2

Where l = length of the rectangular object, w = width of the rectangular object, h = height of the rectangular object.

make h the subject of the equation

h = V/lw........... Equation 3

Given: V = 2.57×10⁻⁴ m³, l = 0.047 m, w = 0.061 m.

Substitute into equation 3

h = 2.57×10⁻⁴/(0.047×0.061)

h = 0.896 m

h = 89.6 cm

5 0
3 years ago
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