Answer:
The wavelength and frequency of light are closely related. The higher the frequency, the shorter the wavelength. Because all light waves move through a vacuum at the same speed, the number of wave crests passing by a given point in one second depends on the wavelength.
Explanation:
The frequency of a light wave is how many waves move past a certain point during a set amount of time -- usually one second is used. Frequency is generally measured in Hertz, which are units of cycles per second. Color is the frequency of visible light, and it ranges from 430 trillion Hertz (which is red) to 750 trillion Hertz (which is violet). Waves can also go beyond and below those frequencies, but they're not visible to the human eye. For instance, radio waves are less than one billion Hertz; gamma rays are more than three billion billion Hertz.Wave frequency is related to wave energy. Since all that waves really are is traveling energy, the more energy in a wave, the higher its frequency. The lower the frequency is, the less energy in the wave. Following the above examples, gamma rays have very high energy and radio waves are low-energy. When it comes to light waves, violet is the highest energy color and red is the lowest energy color. Related to the energy and frequency is the wavelength, or the distance between corresponding points on subsequent waves. You can measure wavelength from peak to peak or from trough to trough. Shorter waves move faster and have more energy, and longer waves travel more slowly and have less energy.Aside from the different frequencies and lengths of light waves, they also have different speeds. In a vacuum, light waves move their fastest: 186,000 miles per second (300,000 kilometers per second). This is also the fastest that anything in the universe moves. But when light waves move through air, water or glass, they slow down. That's also when they bend and refract.
Radio waves have many uses—the category is divided into many subcategories, including microwaves and electromagnetic waves used for AM and FM radio, cellular telephones and TV.
The lowest commonly encountered radio frequencies are produced by high-voltage AC power transmission lines at frequencies of 50 or 60 Hz. These extremely long wavelength electromagnetic waves (about 6000 km) are one means of energy loss in long-distance power transmission.
Extremely low frequency (ELF) radio waves of about 1 kHz are used to communicate with submerged submarines. The ability of radio waves to penetrate salt water is related to their wavelength (much like ultrasound penetrating tissue)—the longer the wavelength, the farther they penetrate. Since salt water is a good conductor, radio waves are strongly absorbed by it; very long wavelengths are needed to reach a submarine under the surface.
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The speed of the wave in the string is 83.4 m/s
Explanation:
For a standing wave in a string, the speed of the wave is given by the equation:
![v=\frac{1}{2L}\sqrt{\frac{T}{m/L}}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B1%7D%7B2L%7D%5Csqrt%7B%5Cfrac%7BT%7D%7Bm%2FL%7D%7D)
where
L is the length of the string
T is the tension in the string
m is the mass of the string
In this problem, we have:
L = 0.72 m
m = 4.2 g = 0.0042 kg
T = 84.1 N
Solving the equation, we find the speed of the wave:
![v=\frac{1}{2(0.72)}\sqrt{\frac{84.1}{0.0042/0.72}}=83.4 m/s](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B1%7D%7B2%280.72%29%7D%5Csqrt%7B%5Cfrac%7B84.1%7D%7B0.0042%2F0.72%7D%7D%3D83.4%20m%2Fs)
Learn more about waves:
brainly.com/question/5354733
brainly.com/question/9077368
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Answer:
Explanation:
The <u>centripetal acceleration</u>
of an object moving in a uniform circular path is given by the following equation:
(1)
Where:
is the tangential velocity
is the radius of the circle
On the other hand, the tangential velocity is expressed as:
(2)
Where
is the angular velocity, which can be found knowing the child makes 5 revolutions in 13.4s:
(3)
Substituting (3) in (2):
(4)
(5)
Substituting (5) in (1):
(6)
Finally:
Answer:
Coefficient of friction will be 0.296
Explanation:
We have given initial speed of the stone u = 8 m /sec
It comes to rest so final speed v = 0 m /sec
Distance traveled before coming to rest s = 11 m
According to third equation of motion
![v^2=u^2+2as](https://tex.z-dn.net/?f=v%5E2%3Du%5E2%2B2as)
So ![0^2=8^2+2\times a\times 11](https://tex.z-dn.net/?f=0%5E2%3D8%5E2%2B2%5Ctimes%20a%5Ctimes%2011)
![a=\frac{-64}{22}=-2.90m/sec^2](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B-64%7D%7B22%7D%3D-2.90m%2Fsec%5E2)
Acceleration due to gravity ![g=9.8m/sec^2](https://tex.z-dn.net/?f=g%3D9.8m%2Fsec%5E2)
We know that acceleration is given by
![a=\mu g](https://tex.z-dn.net/?f=a%3D%5Cmu%20g)
So ![2.90=9.8\times \mu \\](https://tex.z-dn.net/?f=2.90%3D9.8%5Ctimes%20%5Cmu%20%5C%5C)
![\mu =\frac{2.9}{9.8}=0.296](https://tex.z-dn.net/?f=%5Cmu%20%3D%5Cfrac%7B2.9%7D%7B9.8%7D%3D0.296)
So coefficient of friction will be 0.296