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vredina [299]
3 years ago
13

A 55 kg person moves at the constant speed of 7 m/s along a straight stretch of track for 20s. How far does he travel in this ti

me ?
Physics
1 answer:
crimeas [40]3 years ago
6 0
By definition,
Distance = Speed * Time

Therefore the distance traveled is
(7 m/s)*(20 s) = 140 m

Answer: 140 m
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The oscillating electric field in a plane electromagnetic wave is given by <img src="https://tex.z-dn.net/?f=%7B50%5Csin%20%28%5
Scorpion4ik [409]

Here, we are given with:

{:\implies \quad \longrightarrow \begin{cases}\sf E_{0}= 50\: V/m\\ \sf \nu = 2\times 10^{7}Hz\end{cases}}

(a) So now, we can thus obtain

{:\implies \quad \sf \omega =2\pi \nu}

{:\implies \quad \sf \omega =2\pi (2\times 10^{7})}

{:\implies \quad \boxed{\bf{\omega = 4\pi \times 10^{7}\: s^{-1}}}}

Now, finding \lambda

{:\implies \quad \sf \lambda =\dfrac{c}{\omega}=\dfrac{3\times 10^{8}}{4\pi \times 10^{7}}}

{:\implies \quad \boxed{\bf{\lambda \approx 2.39\:m}}}

Now, finding k

{:\implies \quad \sf k=\dfrac{2\pi}{\lambda}=\dfrac{200\pi}{239}}

{:\implies \quad \boxed{\bf{k\approx 2.63\:m^{-1}}}}

Thus, expression for the electric field is:

{:\implies \quad \boxed{\bf{E=50\sin \bigg(4\pi \times 10^{7}t-\dfrac{263x}{100}\bigg)}}}

(b) Now, here

{:\implies \quad \sf B_{0}=\dfrac{E_{0}}{c}=\dfrac{50}{3\times 10^{8}}}

{:\implies \quad \boxed{\bf{B_{0}\approx 16.67×10^{-7}\:T}}}

Thus, expression for the magnetic field:

{:\implies \quad \boxed{\bf{B_{y}=16.67\times 10^{-7}\sin \bigg(4\pi \times 10^{7}t-\dfrac{263x}{100}\bigg)\:T}}}

(c) The electromagnetic wave propagates along Z-axis

4 0
2 years ago
A capacitor is charged until it holds 5.0 j of energy. it is then connected across a 10-kω resistor. in 13.6 ms , the resistor d
prohojiy [21]

Answer:

The capacite is C=5.32 uF using the equations of voltage and energy in capacitance  

Explanation:

The energy holds is 5 J and the resistor dissipates 2J so the energy total is 3J

Using:

V_{t}= V_{o}e^{\frac{-t}{R*C} }

Voltage in this case is the energy dissipated so

E_{t}= E_{o}e^{\frac{-t}{R*C} }

\frac{\sqrt{E_t} }{\sqrt{E_o} } = e^{\frac{-t}{R*C} }

\frac{\sqrt{3 J} }{\sqrt{5J} } = e^{\frac{-13.6ms}{10kw*C} }

Using the equation to find capacitance

ln 0.775= e^{\frac{-13.6 x10^{3} }{10x10^{3}*C }} \\ln(0.775)= ln * e^{\frac{-13.6 x10^{3s} }{10x10^{3}*C }} \\\\ln(0.775)= {\frac{-13.6 x10^{3} }{10x10^{3}*C }} \\C= \frac{-13.6 x10^{-3} }{10x10x^{3}*ln(0.775) }

C= 5.32x10^{-6} F

C= 5.32 uF because u is the symbol for micro that is equal to 10^{-6}

8 0
3 years ago
HELPPP WILL MARK BRAINLIST What type of image is formed by a lens if m= 2.7?
Gelneren [198K]

Answer:

the answer is C

Explanation:

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Explanation:

Solar technologies convert sunlight into electrical energy either through photovoltaic (PV) panels or through mirrors that concentrate solar radiation. This energy can be used to generate electricity or be stored in batteries or thermal storage.

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