Answer:
<h2>42.67N</h2>
Explanation:
Step one:
<u>Given </u>
mass m= 0.32kg
intital velocity, u= 14m/s
final velocity v= 22m/s
time= 0.06s
Step two:
<u>Required</u>
Force F
the expression for the force is
F=mΔv/t
F=0.32*(22-14)/0.06
F=(0.32*8)/0.06
F=2.56/0.06
F=42.67N
The average force exerted on the bat 42.67N
Answer:
a. Effort = 960 Newton
b. Mechanical advantage (M.A) = 0.625
c. Velocity ratio (V.R) = 1.67
Explanation:
<u>Given the following data;</u>
- Load = 600 N
- Length of crowbar = 200 cm
- Length of load arm = 0.75 m
<u>Conversion:</u>
100 cm = 1 m
X cm = 0.75 m
Cross-multiplying, we have;
X = 0.75 * 100 = 75 cm
First of all, we would find the effort arm;
Effort arm = length of crow bar - length of load arm
Effort arm = 200 - 75
Effort arm = 125 cm
Next, we would determine the mechanical advantage (M.A) of the crow bar;

Substituting the values into the formula, we have;

<em>M.A = 0.625</em>
To find the effort of the crow bar;

Making "effort" the subject of formula, we have;


<em>Effort = 960 Newton</em>
Lastly, we would determine the velocity ratio (V.R);


<em>V.R = 1.67</em>
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