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2 years ago

A skateboarder traveling with an initial velocity 9.0 meters per second,

Physics

1 answer:

meriva2 years ago

4 0

Answer:

25m/s

Steps:

First, The equation v= u + a * t shows us what we need to find, (the finale velocity).

Second, we substitute the values given:

v= 9m/s + 4m/s2 * 4s

Last, We calculate the values:

Multiply 4m/s2 * 4s = 16m/s

Add 9m/s + 16m/s

Answer: 25m/s

Hope this helps :)

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The force required is 319 N

Explanation:

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$F_f = \mu W$

where

$\mu$ is the coefficient of friction

W is the weight of the object

Therefore, in order to put the object in motion, the force applied must be greater than this value.

For the pile of leaves in this problem, we have:

$\mu = 0.55$ (coefficient of friction)

$W=580 N$ (weight of the leaves)

Substituting, we find:

$F=(0.55)(580)=319 N$

Learn more about force of friction:

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A group of protons and neutrons surrounded by electrons

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What happens when you compress a gas?

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The density increases.
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A roller coaster starts from rest at its highest point and then descends on its (frictionless) track. its speed is 40 m/s when i

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Given that,

Initial velocity , Vi = 0

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Distance can be calculated as,

2as = Vf² - Vi²

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s = 81.55 m

For half height, that is, s = 40.77m

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2as = Vf² - Vi²

2 * 9.81 * 40.77 = Vf² - 0²

Vf² = 800

Vf = 28.28 m/s

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Answer:

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Explanation:

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