Answer is: Na₂SO₄ (sodium sulfate).
The solubility of sodium sulfate increases up to 32.38°C and than decreases at higher temperatures, the solubility becomes almost independent of temperature.
At 32.38°C it releases of crystal water and melting of the hydrated salt.
Sodium sulfate is the white, inorganic compound.
Sodium sulfate is highly soluble in water.
Balanced equation(That should be NaClO_3)
Remember that it's a ionic equation not general equation
So
We have to balance it accordingly
Answer: Hello, There! Your Answer is Below
2.4 x 1024 ions
Explanation:
220 g of CaCl₂ = X moles
Solving for X,
X = (220 g × 1 mol) ÷ 110.98 g
X = 1.98 moles
As,
1 mole contained = 1.20 × 10²⁴ Cl⁻ Ions
Then,
1.98 mole will contain = X Cl⁻ Ions
Solving for X,
X = (1.98 mol × 1.20 × 10²⁴ Ions) ÷ 1mol
X = 2.38 × 10²⁴ Cl⁻ Ions
Hope this Helps!
Have a great DAy!
`August~
To determine the heat required in order to decompose a certain amount of a substance, we need information on the heat needed to decompose one mole of the substance. This value are readily available online and other sources. For this reaction, the heat needed is 129 kJ per 2 mol of NaHCO3. We calculate as follows:
129 KJ / 2 mol NaHCO3 (1 mol / 84.01 g ) (25.5 g NaHCO3 ) = 19.58 kJ of heat is needed.
