Answer:
2486 mmHg
Explanation:
Gay-Lussac's Law states the pressure varies directly with temperature when volume remains constant:
P₁/T₁ = P₂/T₂
Where P₁ and T₁ are initial pressure and temperature and P₂ and T₂ are final pressure and temperatue.
The problem says initial pressure is 721 mmHg, initial temperature is 25°C and final temperature is 755°C. The question is final pressure.
°C must be converted to absolute temperature (K), thus:
25°C + 273,15 = 298,15 K
755°C + 273,15 = 1028,15 K
Thus, pressure P₂ is:
(T₂·P₁) / T₁ = P₂
1028,15K · 721mmHg / 298,15 K = 2486 mmHg
I hope it helps!
Answer: 
Explanation:
Volume of metal = volume of water displaced = (30.0 - 25.0) ml = 5.0 ml
Density of metal = 5.50 g/ml
Mass of metal =
Volume of water = 25.0 ml
Density of metal = 1.0 g/ml
Mass of metal =
As we know that,
![-[m_1\times c_1\times (T_{final}-T_1)]=[m_2\times c_2\times (T_{final}-T_2)]](https://tex.z-dn.net/?f=-%5Bm_1%5Ctimes%20c_1%5Ctimes%20%28T_%7Bfinal%7D-T_1%29%5D%3D%5Bm_2%5Ctimes%20c_2%5Ctimes%20%28T_%7Bfinal%7D-T_2%29%5D)
.................(1)
where,
q = heat absorbed or released
= mass of metal = 27.5 g
= mass of water = 25.0 g
= final temperature = ?
= temperature of metal = 
= temperature of water = 
= specific heat of lead = ?
= specific heat of water= 
Now put all the given values in equation (1), we get
![27.5g\times c_1\times (41.0-153)^0C=[25.0g\times 4.814J/g^0C\times (41.0-25.0)^0C]](https://tex.z-dn.net/?f=27.5g%5Ctimes%20c_1%5Ctimes%20%2841.0-153%29%5E0C%3D%5B25.0g%5Ctimes%204.814J%2Fg%5E0C%5Ctimes%20%2841.0-25.0%29%5E0C%5D)
Thus the specific heat of the unknown metal sample is
B. The lines show where a phase change happens to a substance
The rate of the reaction is measurable quantity that refers to the amount or how much is are chemical substances reagents used up or converted into the product over some period of time.
Rate = change in the amount/time.
This can indirectly be observed through many ways, such as the volume of gas given off if the byproduct is a gas being produced, the colour of the solution etc.
Answer:
Your answer would be D.) Convection. I hope this helps you! :)
