Question

CuSO4 absorbs light strongly at a wavelength of 635 nm. Consider that you measure the initial intensity of light, Io, entering the solution at 635 nm, and the intensity of light passing through the solution, I, at 635 nm. Sample 1: 0.400 M CuSO4 Sample 2: 0.200 M CuSO4 Which of the following statements is true? Group of answer choices The percent transmittance of light, %T, will be higher for Sample 1 compared to Sample 2. The percent transmittance of light, %T, will be the same for Sample 1 compared to Sample 2. The percent transmittance of light, %T, will be lower for Sample 1 compared to Sample 2.

Answer 1

Answer:

The right statement is "The percent transmittance of light, %T, will be higher for Sample 1 compared to Sample 2."

Explanation:

The Beer-Lambert Law states that the absorbance is directly proportional to the concentration of the substance.

Absorbance = εLc

ε: molar absorptivity coeficient

L: optical path length

c: molar concentration

Therefore, if ε and L are the same, the higher the concentration, the higher the absorbance and the lower the transmitance.

Since sample 1 has a higher concentration of CuSO₄ than sample 2, sample 1 has a higher absorbance and lower percent transmittance.