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2 years ago

C3H8 +502 + 3CO2 + 4H2O

Chemistry

1 answer:

astra-53 [7]2 years ago

5 0

Answer:

Explanation:

first, you calculate the amount of O2 in moles:

98.0 ÷ 32 = 3.0625

second, the ratio if O2/C3H8 is 5 so you need to calculate O2 in moles with that:

3.0625 ÷ 5 = 0.6125

third, the amount of CO2 in moles also can be calculate by the ratio of C3H8/CO2 which is 3

0.6125 × 3 = 1.8375

then multiply CO2 in moles by its molar mass which is 44 g/mol

1.8375 × 44 = 80.85g

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2 years ago

What is the empirical formula of a compound containing 5.03 grams carbon, 0.42 grams hydrogen, and 44.5 grams chlorine?

djverab [1.8K]

The empirical formula of the compound is CHCl₃.

<h3>Calculation:</h3>

Given,

Mass of carbon = 5.03 g

Mass of hydrogen = 0.42 g

Mass of chlorine = 44.5 g

Molecular weight of carbon = 12 g

Molecular weight of hydrogen = 1 g

Molecular weight of chlorine = 35.4 g

First, calculate the moles of each element,

Moles = given mass/ molecular weight

Moles of carbon = 5.03/12 = 0.42

Moles of hydrogen = 0.42/1 = 0.42

Moles of chlorine = 44.5/ 35.4 = 1.26

Divide the moles of each element by the smallest number of moles,

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0.42 mol of H/ 0.42 = 1 H

1.26 mol of Cl/0.42 = 3 Cl

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Therefore the empirical formula of the compound will be CHCl₃.

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Answer:

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