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sasho [114]
2 years ago
9

What is the solution set of the equation? x-11/x 4 =2-4/x?

Mathematics
1 answer:
maxonik [38]2 years ago
5 0
We have:

(X-11)/x^4 = 2 - 4/x

Let's pass x^4 to the right side of equation

(X-11) = x^4.(2 - 4/x)

Use the disttibutive

x - 11 = 2x^4 - 4x^4 / x

Look:

4x^4 / x = 4x^3

Then,

X - 11 = 2x^4 -4x^3

2x^4 - 4x^3 - x + 11 = 0

Let's to use the derivative method:

Let f(x) = 2x^4 - 4x^3 - x +11

Then,

f(x)' = 2.(4).x^3 - 4.(3).x^2 -1

f(x)' = 8x^3 -12x^2 -1

The root to the equation is aproximately X = 1,56

This value would be the minumum or local maximum.

Replacing in the 2 derivative the value of X = 1,56

f(x)'' = 24x^2 - 24x

f(x)'' = 24(1,56)^2 - 24.(1,56)

f(x)" = 20,96

Second tge rule of derivative

If f(x)" > 0

X is point of minumum

Or

If f(x)" < 0

X is point of maximum

Then,

X = minumum in 1,56


Now, let's to replace the value of X = 1,56 in the original equation


f(x) = 2x^4 - 4x^3 - x +11

f(x) = 2.(1,56)^4 - 4.(1,56)^3 -1,56 +11

f(x) ~ 6, 1


We know too:

11 It's where it cuts the axis "Y"


Look the picture here down,

There is not solution to this question!


I hope this has helped!



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Step-by-step explanation:

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2 years ago
Given that (ax^2 + bx + 3) (x + d) = x^3 + 6x^2 + 11x + 12<br> a + 2b - d = ?
Mariulka [41]

Answer:

Let's solve for a.

(ax2+bx+3)(x+d)=x3+6x2+11x+12a+2b−d

Step 1: Add -12a to both sides.

adx2+ax3+bdx+bx2+3d+3x+−12a=x3+6x2+12a+2b−d+11x+−12a

adx2+ax3+bdx+bx2−12a+3d+3x=x3+6x2+2b−d+11x

Step 2: Add -bdx to both sides.

adx2+ax3+bdx+bx2−12a+3d+3x+−bdx=x3+6x2+2b−d+11x+−bdx

adx2+ax3+bx2−12a+3d+3x=−bdx+x3+6x2+2b−d+11x

Step 3: Add -bx^2 to both sides.

adx2+ax3+bx2−12a+3d+3x+−bx2=−bdx+x3+6x2+2b−d+11x+−bx2

adx2+ax3−12a+3d+3x=−bdx−bx2+x3+6x2+2b−d+11x

Step 4: Add -3d to both sides.

adx2+ax3−12a+3d+3x+−3d=−bdx−bx2+x3+6x2+2b−d+11x+−3d

adx2+ax3−12a+3x=−bdx−bx2+x3+6x2+2b−4d+11x

Step 5: Add -3x to both sides.

adx2+ax3−12a+3x+−3x=−bdx−bx2+x3+6x2+2b−4d+11x+−3x

adx2+ax3−12a=−bdx−bx2+x3+6x2+2b−4d+8x

Step 6: Factor out variable a.

a(dx2+x3−12)=−bdx−bx2+x3+6x2+2b−4d+8x

Step 7: Divide both sides by dx^2+x^3-12.

a(dx2+x3−12)

dx2+x3−12

=

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

a=

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

Answer:

a=

−bdx−bx2+x3+6x2+2b−4d+8x/

dx2+x3−12

Step-by-step explanation:

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Answer:

288

Step-by-step explanation:

24 = 8 1/3 % of x

24 = (25/3 * 1/100)x

25/300 x = 24

x = 24 * 300/25

x = 7200/25

x = 288

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