Question

Two toy rockets are launched straight up into the air. The height, in feet, of each rocket at t seconds after launch is given by the polynomial equations shown. Write an equation to find the "difference" in height of Rocket A and Rocket B. Rocket A: -15t^2 + 100t and Rocket B: -14t^2 + 85t+3.

Answer 1

Given:

The height, in feet, of each rocket at t seconds after launch is given by the polynomial equations:

Rocket A: $-15t^2+100t$

Rocket B: $-14t^2+85t+3$

To find:

The equation to find the "difference" in height of Rocket A and Rocket B.

Solution:

The difference in height of Rocket A and Rocket B is:

Difference = Height of Rocket A - Height of Rocket B

$\text{Difference}=(-15t^2+100t)-(-14t^2+85t+3)$

$\text{Difference}=-15t^2+100t+14t^2-85t-3$

$\text{Difference}=(-15t^2+14t^2)+(100t-85t)-3$

$\text{Difference}=-t^2+15t-3$

Therefore, the difference in height of Rocket A and Rocket B is $-t^2+15t-3$.