2x-4≤ 12___<br> 3x+2≤ 20___<br> 11x -50≤ 82__

What is the missing number in the line 415,418,423,427,430

mihalych1998 [28]

This is a good question... but is there multiple choice, i want to know if my answer matches

8 0

3 years ago

An angle measured 10 degrees less than the measure of its complementary angle. Find the measure of both angles

Mazyrski [523]

Answer:

The measure of the angles are 40 degrees and 50 degrees

Step-by-step explanation:

Let

x ----> the measure of one angle in degrees

y ----> the measure of the complementary angle in degrees

we know that

If two angles are complementary, then their sum is equal to 90 degrees

so

$x+y=90$ ----> equation A

we have that

$x=y-10$ ----> equation B

Substitute equation B in equation A and solve for y

$(y-10)+y=90\\2y-10=90\\2y=100\\y=50$

Find the value of x

$x=50-10=40$

therefore

The measure of the angles are 40 degrees and 50 degrees

3 0

3 years ago

If a line crosses the y-axis at (0, 1) and has a slope of , what is the equation of the line?

defon

5y - 4x = 5
5y = 4x + 5
y = 4/5x + 1.....slope of 4/5 and y intercept of (0,1)

6 0

3 years ago

What is the quotient when 4x3 + 2x + 7 is divided by x + 3?

Arte-miy333 [17]

Answer:

The quotient of this division is $(4x^2 -12x + 38)$ . The remainder here would be $-26$ .

Step-by-step explanation:

The numerator $4x^3 + 2x + 7$ is a polynomial about $x$ with degree $3$ .

The divisor $x + 3$ is a polynomial, also about $x$ , but with degree $1$ .

By the division algorithm, the quotient should be of degree $3 - 1 = 2$ , while the remainder shall be of degree $1 - 1 = 0$ (i.e., the remainder would be a constant.) Let the quotient be $a\,x^2 + b\, x + c$ with coefficients $a$ , $b$ , and $c$ .

$4x^3 + 2x + 7 = \left(a\,x^2 + b\, x + c\right)(x + 3)$ .

Start by finding the first coefficient of the quotient.

The degree-three term on the left-hand side is $4 x^3$ . On the right-hand side, that would be $a\, x^3$ . Hence $a = 4$ .

Now, given that $a = 4$ , rewrite the right-hand side:

$\begin{aligned}&\left(4\,x^2 + b\, x + c\right)(x + 3) \cr =& \left(4x^2 + (b\, x + c)\right)(x + 3) \cr =& 4x^2(x + 3) + (bx + c)(x + 3) \cr =& 4x^3 + 12x^2 + (bx + c)(x + 3)\end{aligned}$ .

Hence:

$4x^3 + 2x + 7 = 4x^3 + 12x^2 + (b\,x + c)(x + 3)$

Subtract $\left(4x^3 + 12x^2\right$ from both sides of the equation:

$-12x^2 + 2x + 7 = (b\,x + c)(x + 3)$ .

The term with a degree of two on the left-hand side has coefficient $(-12)$ . Since the only term on the right hand side with degree two would have coefficient $b$ , $b = -12$ .

Again, rewrite the right-hand side:

$\begin{aligned}&\left(-12 x + c\right)(x + 3) \cr =& \left(-12 x+ c\right)(x + 3) \cr =& (-12x)(x + 3) + c(x + 3) \cr =& -12x^2 -36x + (bx + c)(x + 3)\end{aligned}$ .