The kinetic energy (KE) of a 0.155 kg arrow that is shot from ground level, upward at 31.4 m/s, when it is 30.0 m above the ground is 30.85 J
Assuming air friction is negligible,
a = - 9.8 m / s²
u = 31.4 m / s
s = 30 m
v² = u² + 2 a s
v² = 31.4² + ( 2 * - 9.8 * 30 )
v² = 985.96 - 588
v² = 397.96 m / s
KE = 1 / 2 m v²
KE = 1 / 2 * 0.155 * 397.96
KE = 0.0775 * 397.96
KE = 30.85 J
Therefore, the kinetic energy ( KE ) when it is 30.0 m above the ground is 30.85 J
To know more about kinetic energy
brainly.com/question/24360064
#SPJ1
As we know that acceleration due to gravity is given by

here we know that
g = 3.60 m/s^2
M = ?

now we have


so above is the mass of Mars
The object will sail away in a straight line ... continuing in the same direction it was going when the centripetal force stopped.
<span><span>Big Bang- January 1
</span><span>Origin of Milky Way Galaxy- May 1
</span><span>Origin of the solar system- September 9
</span><span>Formation of the Earth- September 14
</span><span>Origin of life on Earth<span>- September 25</span></span></span>