Answer:
The correct answer is true.
Answer:
see solution below
Explanation:
The given resistors are connected in series.
Equivalent resistance in series = 30 + 55 + 15
Equivalent resistance in series Rt = 100 ohms
Since the potential difference in the circuit = 36V
Get the current in the circuit first
I = V/Rt
I = 36/100
I = 0.36A
Get the voltage across 30ohms resistor;
V30 = 0.36 * 30
V30 = 10.8volts
Hence the voltage across the 30ohms resistor is 10.8volts
Get the voltage across 55ohms resistor;
V55 = 0.36 * 55
V55 = 19.8volts
Hence the voltage across the 55ohms resistor is 19.8volts
Get the voltage across 15ohms resistor;
V15 = 0.36 * 15
V15 = 5.4volts
Hence the voltage across the 15ohms resistor is 5.4volts
Answer:
Power output: W=1426.9MW
Explanation:
The power output of the falls is given mainly by its change in potential energy:
The potential energy for any point can be calculated as:
If we consider the base of the falls to be the reference height, at point 2 h=0, so P2=0, and height at point 1 equals 52m:
If we replace m with the mass rate M we obtain the rate of change in potential energy over time, so the power generated:
I believe the correct answer is A, Wave 1 has a longer wavelength and a higher amplitude than wave 2. Both A and B are transverse wave, therefore, the wavelength is the distance between two successful crest (highest point) or two successful trough (lowest point). In this case, wave 1 has a longer wavelength than wave 2. Amplitude is the maximum displacement of particles in a wave on either side from the equilibrium point. From the diagram wave 1 as a higher amplitude compared to wave 2.
Answer:
Explanation:
By Einstein's Equation of photoelectric effect we know that
here we know that
= energy of the photons incident on the metal
= minimum energy required to remove photons from metal
= kinetic energy of the electrons ejected out of the plate
now we know that it requires 351 nm wavelength of photons to just eject out the electrons
so we can say
here we know that
now we have
now by energy equation above when photon of 303 nm incident on the surface