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3 years ago

Most individuals over 65 years of age

Physics

2 answers:

Olin [163]3 years ago

6 0

Suffer from arthritis

Cloud [144]3 years ago

5 0

Most people over 65 lead active independent lives. My mother is 88 years old & she drives & is perfectly able to take care of herself except for always wanting someone to help her with her iPad or computer. If that were a choice, I would pick that!

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In class we calculated the range of a projectile launched on flat ground. Consider instead, a projectile is launched down-slope

zysi [14]

Answer:

With an initial speed of 10m/s at an angle 30° below the horizontal, and a height of 8m, the projectile travels 7.49m horizontally before it lands.

Explanation:

Since the horizontal motion is independent from the vertical motion, we can consider them separated. The horizonal motion has a constant speed, because there is no external forces in the horizontal axis. On the other hand, the vertical motion actually is affected by the gravitational force, so the projectile will be accelerated down with a magnitude $g$ .

If we have the initial velocity $v_o$ and its angle $\theta$ , we can obtain the vertical component of the velocity $v_{oy}$ using trigonometry:

$v_{oy}=v_osin\theta$

Therefore, if we know the height at which the projectile was launched, we can obtain the final velocity using the formula:

$v_{fy}^{2} =v_{oy}^{2}+2gy\\\\ v_{fy}=\sqrt{v_{oy}^{2}+2gy }$

Next, we compute the time the projectile lasts to reach the ground using the definition of acceleration:

$g=\frac{v_{fy}-v_{oy}}{\Delta t} \\\\\Delta t= \frac{v_{fy}-v_{oy}}{g}=\frac{\sqrt{v_{oy}^{2}+2gy} -v_{oy}}{g}$

Finally, from the equation of horizontal motion with constant speed, we have that:

$x=v_{ox}\Delta t= v_{ox}\frac{\sqrt{v_{oy}^{2}+2gy} -v_{oy}}{g}$

For example, if the projectile is launched at an angle 30° below the horizontal with an initial speed of 10m/s and a height 8m, we compute:

$v_{ox}=10\frac{m}{s} cos30=8.66\frac{m}{s}\\v_{oy}=10\frac{m}{s} sin30=5\frac{m}{s}\\\\x=8.66\frac{m}{s} \frac{\sqrt{(5\frac{m}{s}) ^{2}+2(9.8\frac{m}{s^{2}})8m}-5\frac{m}{s} }{9.8\frac{m}{s^{2} } } =7.49m$

In words, the projectile travels 7.49m horizontally before it lands.

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4 years ago

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3 years ago

The diagram below shows the reactants and products of a chemical reaction. What property of reactions does this diagram illustra

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Based on the chemical reaction, Carbon reacts with Oxygen would yield Carbon Dioxide, we can imply that the "<span>Atoms are always conserved during chemical reactions." It is one of the fundamental concepts in chemistry wherein the mass is always conserved in a reaction since it can't be created nor destroyed.</span>

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3 years ago

Suppose a logs mass is 5kg .after burning,the mass of the ash is 1kg .explain what may have happened to the other 4kg

BigorU [14]

The "missing" 4 kg may have escaped the scene of the fire in the
form of hot gases, and as particles of soot and ash that were seen
leaving in the form of "smoke".

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3 years ago

The image produced by an object is –10.0 cm from a concave mirror that has a focal length of 5.0 cm. The distance of the object

Gennadij [26K]

Given:
Focal length: 5.0 cm
image produced: -10.0 cm

mirror equation: 1/di + 1/do = 1/f

Look for the actual distance of the object from the mirror. Solve for do.

1/do + 1/(-10) = 1/5
1/do = 1/5 + 1/10
1/do = (1/5 * 2/2) + (1/10 * 1/1)
1/do = 2/10 + 1/10
1/do = 3/10
10 = 3do
10/3 = do
3.33 = do

The distance of the object from the mirror, rounded to the nearest centimeter is 3 cm.

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4 years ago

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