The angular velocity of the propeller is 136.1 rad/s; linear velocity is 153.1 m/s; centripetal acceleration 20835.2 m/s² and 2123.8 g.
<h3>What is the angular velocity of the propeller?</h3>
The angular velocity of the propeller in rad/s is given as follows:
1300 rev/min = 1300 * 2π/60 = 136.1 rad/s.
b. The linear velocity, v = radius * angular velocity
Linear velocity, v = 2.25/2 * 136.1
v = 153.1 m/s
c. Centripetal acceleration,
Centripetal acceleration in terms of g;
Therefore, the angular velocity of the propeller is 136.1 rad/s; linear velocity is 153.1 m/s; centripetal acceleration 20835.2 m/s² and 2123.8 g.
Learn more about angular velocity and centripetal acceleration at: brainly.com/question/10703948
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To my knowledge, it would be the day.
<em><u>one year: earth </u></em><em><u>revolves around the sun</u></em>
<em><u> one</u></em><em><u> month: moon revolution around the earth</u></em>
<em><u>one</u></em><em><u> day: the earth rotation about its axis</u></em>
However, nothing above indicates what day of the week it is; you can tell when a day has passed, but not what day of the week is.
Hope this helps!
-Moiselle
1) push down on the end of the lever, and 2) 3/4 of the way from the fulcrum
The pressure is the force divided by the area to which the force is applied, so in this problem it is equal to: