Answer:
6
Step-by-step explanation:
8x+6x+6 = 90
14x = 84
x = 6
The perimeter<span> of an </span>equilateral triangle<span> is 7 </span>inches more than<span> the </span>perimeter<span> of a </span>square<span>, and the </span>side<span> of the </span>triangle<span> is 5 </span>inches<span> longer </span>than<span> the </span>side<span> of the </span>square<span>. </span>Find<span> the </span>side of the triangle<span>. (Hint: An </span>equilateral triangle<span> has three </span>sides the same length<span>.</span>
A heptagon has 7 sides so it would be a pentagon (which has 5 sides)
Answer:
Four/4
Step-by-step explanation:
Add both numbers together.
2+2
4
<h3>Answers are:
sine, tangent, cosecant, cotangent</h3>
Explanation:
On the unit circle we have some point (x,y) such that x = cos(theta) and y = sin(theta). The sine corresponds to the y coordinate of the point on the circle. Quadrant IV is below the x axis which explains why sine is negative here, since y < 0 here.
Since sine is negative, so is cosecant as this is the reciprocal of sine
csc = 1/sin
In quadrant IV, cosine is positive as x > 0 here. So the ratio tan = sin/cos is going to be negative. We have a negative over a positive when we divide.
Because tangent is negative, so is cotangent.
The only positive functions in Q4 are cosine and secant, which is because sec = 1/cos.
