Answer: -
Concentration of PbI₂ = 1.5 x 10⁻³ M
PbI₂ dissociates in water as
PbI₂ ⇄ Pb²⁺ + 2 I⁻
So PbI₂ releases two times the amount of I⁻ as it's own concentration when saturated.
Thus the molar concentration of iodide ion in a saturated PbI₂ solution = [ I⁻] =
= 1.5 x 10⁻³ x 2 M
= 3 x 10⁻³ M
PbI₂ releases the same amount of Pb²⁺ as it's own concentration when saturated.
[Pb²⁺] = 1.5 x 10⁻³ M
So solubility product for PbI₂
Ksp = [Pb²⁺] x [ I⁻]²
=1.5 x 10⁻³ x (3 x 10⁻³)²
= 4.5 x 10⁻⁹
The first answer is B and the second answer is B
Answer:
solid
Explanation:
in the solid state the material will has a fixed shape and volume whatever the container that contains it
where in liquid the shape will be different depending on the container
and in gas state the shape and volume are not definite
Answer:
4.46 °C
Explanation:
Step 1: Given and required data
- Energy absorbed (Q): 4430 J
- Specific heat of water (c): 4.186 J/g.°C
Step 2: Calculate the temperature change
We will use the following expression.
Q = c × m × ΔT
ΔT = Q / c × m
ΔT = 4430 J / (4.186 J/g.°C) × 237 g
ΔT = 4.46 °C
The temperature change is 4.46 °C.