What are the basic properties of the outer shell of an element?

1 answer:

7 0

The number of electrons in the outermost shell of an atom determines its physical and chemical properties. All elements are most stable with 8 electrons (an octet) in their outer shell.

Hope this helps!!

You might be interested in

Calculate the standard reaction enthalpy for the reaction NO2(g) → NO(g) + O(g) given +142.7 kJ/mol for the standard enthalpy of

bulgar [2K]

Answer:

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

Explanation:

$O_2(g) \rightarrow \frac{2}{3}O_3(g),\Delta H^o_{1}=142.7 kJ/mol$ ..[1]

$O_2(g) \rightarrow 2 O(g),\Delta H^o_{2}=498.4 kJ/mol$ ..[2]

$NO(g) + O_3(g)\rightarrow NO_2(g) + O_2(g) ,\Delta H^o_{3} = -200 kJ/mol$ ..[3]

$NO_2(g)\rightarrow NO(g) + O(g),\Delta H^o_{4}=?$ ..[4]

Using Hess's law:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

2 × [4] = [2]- (3 ) × [1] - (2) × [3]

$2\times \Delta H^o_{4}=\Delta H^o_{2} -3\times \Delta H^o_{1}-2\times \Delta H^o_{3}$

$2\times \Delta H^o_{4}=498.4 kJ/mol-3\times 142.7 kJ/mol-2\times -200 kJ/mol$

$2\times \Delta H^o_{4}=470.3 kJ/mol$

$\Delta H^o_{4}=\frac{470.3 kJ/mol}{2}=235.15 kJ/mol$

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

7 0

2 years ago

Anyone know this please and thank you

Bas_tet [7]

Answer:

The correct answer is a hypothesis.

8 0

1 year ago

The variables for part 1 of this experiment include the types of materials, used in the cup, the masses of these materials and t

iVinArrow [24]

So, first off let’s look at what an independent and dependent variable is.

an independent variable doesn’t change when other variables change, therefore making it alone and independent.

a dependent variable changes based on other variables.

so, i don’t have enough information on your experiment to know the answer but think to yourself, what is changing over time based on something else changing (dependent variable) or think does this thing stay the same no matter what (independent variable).

hope this helps!

8 0

2 years ago

A 20.7167 g sample of impure magnesium carbonate was heated to complete decomposition according to the equation mgco3(s) → mgo(s

marishachu [46]

The mass of impure $MgCO_{3}$ is 20.7167 g. The decomposition reaction is as follows: