Physical: abrasion, crystallization, insolation, melting and freezing.
Chemical: hydration, oxidation(rust), carbonic acid action, and hydrolysis
Answer:
Molecular mass of BHT is 204,2 g/mol
Explanation:
To answer this question you need to know that Freezing-point depression (A colligative property) is the decrease of the freezing point of a solvent on the addition of a non-volatile solute. The formula is:
ΔT = Kf m
Where ΔT is the freezing point depression (5,5°C - 4,880°C = 0,62°C
Kf that is freezing point molar constant of the solvent (5,065°C/m)
And m that is molality (moles of solute/kg of solvent). Replacing:
Knowing you have 100,0g of solvent ≡ 0,1000 kg:
=<em> 0,01224 moles of solute </em> <em>≡ BHT</em>
As grams of BHT are 2,500, molecular mass of BHT is:
<em>204,2 g/mol</em>
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I hope it helps
Answer: The last one
Explanation: because Im in the 8th grade and I did this in the 6th
GIVE BRAINLEIST LIKE U PROMISED
Answer:
1) 90.0 mL
2) 11.25 M
3) 0.477 M
4) 144 mL
Explanation:
The main formula that will be used for all these calculations is:
C₁V₁ = C₂V₂
C stands for concentration and V stands for volume and the subscripts 1 and 2 indicate an initial concentration or volume and a final concentration or volume.
For each problem, it's best to start by figuring out what you have and what you need to find. Figure out if you're looking for an initial value or a final value.
1) We need to find the initial volume. So, take what values you have and plug them in and then solve for whatever variable:
5.00 M · V₁ = 500.0mL · 0.900 M - divide by 5.00
C₁ = 90.0 mL
2) This time we're finding the initial concentration:
20.0mL · C₁ = 150.0mL · 1.50 M - divide by 20.0mL
C₂ = 11.25 M
3) Now we're finding the final concentration:
12.00mL · 3.50 M = 88.0mL · C₂ - divide by 88.0mL
C₂ = 0.477 M
4) Finally, we're looking for the final volume:
9.0mL · 8.0 M = 0.50 M · V₂ - divide by 0.50 M
V₂ = 144mL
