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antoniya [11.8K]
2 years ago
11

An earthquake's____ located directly above its_____

Chemistry
1 answer:
Kipish [7]2 years ago
6 0

Answer:

An earthquake's <u>what happens when two blocks of the earth suddenly slip past one another. </u>

located directly above its <u>The epic Center </u>

Explanation:

<h2>Hope this helps you !! </h2>
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After ensuring the equipment is turned off and unplugged what is the next step in cleaning large equipment by hand
Mnenie [13.5K]
Given that the equipment is stationary, we should remove particles (such as food and soil) from around the equipment.

This step ensures that large particles are removed and do not hinder the remaining process of cleaning. After doing so, the next step is to remove the removable parts of the machinery. After this has been done, the cleaning steps may be undertaken.
8 0
3 years ago
The normal freezing point of a certain liquid
stepladder [879]

Answer : The molal freezing point depression constant of X is 4.12^oC/m

Explanation :  Given,

Mass of urea (solute) = 5.90 g

Mass of X liquid (solvent) = 450.0 g

Molar mass of urea = 60 g/mole

Formula used :  

\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{\text{Mass of urea}\times 1000}{\text{Molar mass of urea}\times \text{Mass of X liquid}}

where,

\Delta T_f = change in freezing point

\Delta T_s = freezing point of solution = -0.5^oC

\Delta T^o = freezing point of liquid X= 0.4^oC

i = Van't Hoff factor = 1  (for non-electrolyte)

K_f = molal freezing point depression constant of X = ?

m = molality

Now put all the given values in this formula, we get

[0.4-(-0.5)]^oC=1\times k_f\times \frac{5.90g\times 1000}{60g/mol\times 450.0g}

k_f=4.12^oC/m

Therefore, the molal freezing point depression constant of X is 4.12^oC/m

4 0
3 years ago
Which radiation can only be stopped by thick layers of dense metal? (2 points)
AfilCa [17]
Gamma rays have the highest penetrating power so it can only be stopped by thick layers of dense metal. :)
5 0
4 years ago
Read 2 more answers
9. What is the process of nuclear fusion? *
Pavlova-9 [17]

Answer:

the process of carrying light

5 0
3 years ago
Determine the pHpH of an HFHF solution of each of the following concentrations. In which cases can you not make the simplifying
PIT_PIT [208]

The question is incomplete, complete question is :

Determine the pH of an HF solution of each of the following concentrations. In which cases can you not make the simplifying assumption that x is small? (K_a for HF is 6.8\times 10^{-4}.)

[HF] = 0.280 M

Express your answer to two decimal places.

Answer:

The pH of an 0.280 M HF solution is 1.87.

Explanation:3

Initial concentration if HF = c = 0.280 M

Dissociation constant of the HF = K_a=6.8\times 10^{-4}

HF\rightleftharpoons H^++F^-

Initially

c          0            0

At equilibrium :

(c-x)      x             x

The expression of disassociation constant is given as:

K_a=\frac{[H^+][F^-]}{[HF]}

K_a=\frac{x\times x}{(c-x)}

6.8\times 10^{-4}=\frac{x^2}{(0.280 M-x)}

Solving for x, we get:

x = 0.01346 M

So, the concentration of hydrogen ion at equilibrium is :

[H^+]=x=0.01346 M

The pH of the solution is ;

pH=-\log[H^+]=-\log[0.01346 M]=1.87

The pH of an 0.280 M HF solution is 1.87.

6 0
3 years ago
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