11. Which of the following type of surface is wood?

Hemoglobin, a protein in red blood cells, carries O2 from the lungs to the body's cells. Iron (as ferrous ion, Fe2+) makes up 0.

levacccp [35]

Answer: The number of $Fe^{2+}$ ions in one molecule of hemoglobin are 4.

Explanation:

According to mole concept:

1 mole of an element contains $6.022\times 10^{23}$ number of atoms.

We are given:

Mass of 1 mole of hemoglobin = $6.8\times 10^4g$

Using above equation:

$6.022\times 10^{23}$ number of molecules have a mass of $6.8\times 10^4g$

So, 1 molecule of hemoglobin will have a mass of $\frac{6.8\times 10^4g}{6.022\times 10^{23}}\times 1=1.129\times 10^{-19}g$

It is also given that 0.33 mass % of hemoglobin has $Fe^{2+}$ ions

So, mass of $Fe^{2+}$ ions will be = $\frac{0.33}{100}\times 1.129\times 10^{-19}g=3.7257\times 10^{-22}g$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of iron ion = $3.7257\times 10^{-22}g$

Molar mass of iron ion = 55.85 g/mol

Putting values in above equation, we get:

$\text{Moles of }Fe^{2+}\text{ ion}=\frac{3.7257\times 10^{-22}g}{55.85g/mol}=6.67\times 10^{-24}mol$

Using mole concept:

1 mole of an element contains $6.022\times 10^{23}$ number of atoms.

So, $6.67\times 10^{-24}$ moles of hemoglobin will contain = $6.022\times 10^{23}\times 6.67\times 10^{-24}=4$

Hence, the number of $Fe^{2+}$ ions in one molecule of hemoglobin are 4.

8 0

3 years ago

As the pressure on a given sample of a gas increases at constant temperature, the mass of the sample.

cricket20 [7]

Should remain the same, the volume will decrease.

4 0

2 years ago

Can someone help me pls

Inessa [10]

Answer:

The heat would flow from the hot solid to the cool solid until all temperatures are near equal.

4 0

3 years ago

How many helium atoms are there in a helium blimp containing 535 kg of helium?

svetoff [14.1K]

Helium atom's Atomic Weight = He = 4.0026 g/mol. Avagrado's number is = 6.023 x 10^23 molecules / mol. In order to find the number of atoms in 535kg of helium blimp. First we need to convert the weight of 535 kg to mol which can be done by multiplying the atomic weight of helium into present atom with respect to grams. 535 kg converted into grams ---> 535000 g There fore 535000 g X 4.0026 g/mol = 133,663 mol. (Note The grams will get cancel as per multiplication rules) Multiplying the avagadro's number with the equation we get: 133,663 mol *6.0221415 Ă— 10^23 molecules/mol= 8.04919303 Ă— 10^28 molecules. Since Helium is having 2 Atoms : 8.04919303 Ă— 10^28 molecules *2= 1.60983861 Ă— 10^29 atoms The No of Helium atoms in 535 kg of helium is 1.61 x 10^29.

4 0

3 years ago

Classify the compound below as an alkane, alkene, alkyne, alcohol, aldehyde, amine, and so forth

Gnoma [55]

Answer:

Organic compounds are those which are derivatives of hydrocarbons. They are classified into following functional groups.

Alkane:

Alkane are simplest hydrocarbons.
They have general formula CnH2n+2. These hydrocarbons contain single bond.
For example ethane , H3C----CH3.

Alkene:

Alkene are most reactive.
They have general formula CnH2n.
These contain double bond in their structure.
For example , ethene, H2C=CH2

Alkyne:

These are less less reactive as compare to alkenes.
They have general formula CnH2n-2.
They contain triple bonds in their structure.
For example Acetylene HC≡CH

Alcohol:

Alcohol have functional group OH. They have general formual R---OH, R may be alkyl group.For example Ethanol H3CH2C---OH

Amine:

Amine contain NH2 F.G.
They have general formula R---NH2.
There are three types of amine like primary, secondary and tertiary amine.
For example H3CH2C---NH2

Aldehyde:

Aldehydes have CHO F.G .
They have general formula R--CHO.
For example H3CH2C---CHO

Ketone:

Ketones have R--CO--R functional group.
For example acetone H3C---CO---CH3

Carboxylic acid:

They functional group COOH.
Their general formula is R---COOH.
For example Acetic acid H3C---COOH

6 0

3 years ago