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sasho [114]
2 years ago
15

Which of the following would result in a decrease in entropy?

Chemistry
1 answer:
Vika [28.1K]2 years ago
8 0
The answer would be C
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What is the independent variable for this experiment?
Sav [38]

Answer:

the type of drink they consumed each day

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3 years ago
Can someone please help me
mrs_skeptik [129]
The answer will be D
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How many bromine atoms are present in 39.4 g of CH2Br2
strojnjashka [21]
37.8 g CH2Br2 X (1 mol CH2Br2 / 173.83 g) = 4.60X10^-3 mol CH2Br2 

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3 years ago
if the particles formed through fission have less mass than the starting material has the laaw of conversation of energy been br
Alexxandr [17]

The law of conservation of energy has not been broken, provided energy is released from the fission process.

<h3>What is the law of conservation of energy?</h3>

The law states that the total energy of a process is conserved. That is, the total energy or mass of a system before and after undergoing processing remains the same. However, some of the mass/energy can be converted to another form.

When a material undergoes fission, the sum total of the mass of the particles formed should be equal to the mass of the starting materials, provided that all other things remain the same.

However, if energy is released from the fission process, it means that some of the mass of the starting materials has been converted to energy and released to the environment.

More on the law of conservation of energy can be found here: brainly.com/question/20971995

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3 0
2 years ago
8. The time period of artificial satellite in a circular orbit of radius R is T. The radius of the orbit in which time period is
Elena-2011 [213]

Explanation:

It is given that,

The time period of artificial satellite in a circular orbit of radius R is T. The relation between the time period and the radius is given by :

T^2\propto R^3

The radius of the orbit in which time period is 8T is R'. So, the relation is given by :

(\dfrac{T}{T'})^2=(\dfrac{R}{R'})^3

(\dfrac{T}{8T})^2=(\dfrac{R}{R'})^3  

\dfrac{1}{64}=(\dfrac{R}{R'})^3

R'=4\times R

So, the radius of the orbit in which time period is 8T is 4R. Hence, this is the required solution.  

4 0
3 years ago
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