Answer: An atom in an excited state contains more of kinetic energy than the same atom in the ground state.
Explanation:
Kinetic energy is the energy acquired by an object due to its motion. And, thermal energy is the internal energy of an object arisen because of the kinetic energy present within the molecules of the object.
Potential energy is the energy acquired by an object due to its position.
The total energy present at the center of mass of an object is known as mass-energy.
So, when an atom gets excited then it means it is gaining kinetic energy due to which it moves from its initial position after getting excited.
Thus, we can conclude that an atom in an excited state contains more of kinetic energy than the same atom in the ground state.
Electronegativity is your answer.
Explanation:
Acceleration (a) = 600 m/s²
Mass (m) = 300 kg
Force (F) = ?
We know
F = m * a
= 300 * 600
=180000 Newton
The force acting on the object is 18000 Newton.
The boiling point of water at 1 atm is 100 degrees celsius. However, when water is added with another substance the boiling point of it rises than when it is still a pure solvent. This called boiling point elevation, a colligative property. The equation for the boiling point elevation is expressed as the product of the ebullioscopic constant (0.52 degrees celsius / m) for water), the vant hoff factor and the concentration of solute (in terms of molality).
ΔT(CaCl2) = i x K x m = 3 x 0.52 x 0.25 = 0.39 °C
<span> ΔT(Sucrose) = 1 x 0.52 x 0.75 = 0.39 </span>°C<span>
</span><span> ΔT(Ethylene glycol) = 1 x 0.52 x 1 = 0.52 </span>°C<span>
</span><span> ΔT(CaCl2) = 3 x 0.52 x 0.50 = 0.78 </span>°C<span>
</span><span> ΔT(NaCl) = 2 x 0.52 x 0.25 = 0.26 </span>°C<span>
</span>
Thus, from the calculated values, we see that 0.75 mol sucrose dissolved on 1 kg water has the same boiling point with 0.25 mol CaCl2 dissolved in 1 kg water.
I think the answer to that is B