Assuming equal concentrations and complete dissociation, rank these aqueous solutions by their freezing points from highest to l
1 answer:
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Answer:
The molar mass of the gas is 44 g/mol
Explanation:
It is possible to solve this problem using Graham's law that says: Rates of effusion are inversely dependent on the square of the mass of each gas. That is:
If rate of effusion of nitrogen is Xdistance / 48s and for the unknown gas is X distance / 60s and mass of nitrogen gas is 28g/mol (N₂):
6,61 = √M₂
44g/mol = M₂
<em>The molar mass of the gas is 44 g/mol</em>
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Answer:
C. Plug the unknowns into the ideal gas law formula.
Explanation:
Gay-Lussac's law states that:
"For a constant mass of an ideal gas kept at constant volume, the pressure of the gas is directly proportional to its absolute temperature"
Mathematically, it can be written as:
where
p1 is the initial pressure
T1 is the initial temperature (in Kelvin)
p2 is the final pressure
T2 is the final temperature (in Kelvin)
Therefore, in order to solve for one of the 4 variables, the following steps must be adopted:
A. List your knowns and unknowns.
B. Convert temperature to kelvin.
D. Solve for the unknown.
While the following step is not needed:
C. Plug the unknowns into the ideal gas law formula.
Because we do not need to use the ideal gas law formula.
Answer:
=> 2.8554 g/mL
Explanation:
To determine the formula to use in solving such a problem, you have to consider what you have been given.
We have;
mass (m) = 16.59 g
Volume (v) = 5.81 mL
From our question, we are to determine the density (rho) of the rock.
The formula:
Substitute the values into the formula:
= 2.8554 g/mL
Therefore, the density (rho) of the rock is 2.8554 g/mL.