Answer:
Part 1) Voltage in secondary windings is 61.08 Volts
Part 2) Current in secondary windings is 0.53 Amperes
Explanation:
The potential developed in the primary and secondary winding of a transformer are related as

where
Np no of turns in primary coil
Ns no of turns in secondary coil
Vp Voltage of turns in primary coil
Vs Voltage of turns in secondary coil
Applying values in the formula we get

Part 2)
Using Ohm's law the current is given by

Answer: 0.798 m
Explanation:
Given
Mass of the spring oscillator, m = 1.48 kg
Force constant of the spring, k = 35.4 N/m
Speed of oscillation, v = 3.9 m/s
Kinetic Energy = 1/2 mv²
Kinetic Energy = 1/2 * 1.48 * 3.9²
KE = 0.5 * 22.5108
KE = 11.26 J
Using the law of conservation of Energy. The Potential Energy of the system is equal to Kinetic Energy of the system
KE = PE
PE = 1/2kx²
11.26 = 1/2 * 35.4 * x²
11.26 = 17.7x²
x² = 11.26 / 17.7
x² = 0.6362
x = √0.6362
x = 0.798 m
A plant that normally grows in one environment not grow well in a different environment because every flower is different around the certain providing environment.