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diamong [38]
3 years ago
12

An electron in an atom's orbital shell, labeled X in the model below, released enough energy to move to a different orbital shel

l. Which of the two orbital shells would the electron have the possibility of moving to
Physics
1 answer:
Delicious77 [7]3 years ago
7 0

Answer:

Lower energy shell which will be nearer to the nucleus.

Explanation:

When electron move from one energy level to another, an electron must gain or lose just the right amount of energy.

When atoms releases energy, electrons move into lower energy levels.  The electrons in the shells aways from the nucleus have more energy as compared to the electrons in the nearer shells.

Electrons with the lowest energy are found closest to the nucleus, where the attractive force of the positively charged nucleus is the greatest. Electrons that have higher energy are found further away

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A certain electric furnace consumes 24 kw when it is connected to a 240-v line. what is the resistance of the furnace?
weeeeeb [17]

One very handy electrical formula is

Power dissipated by a resistance = (Voltage)²/(resistance) .

24 kilowatts = (240 v)² / Resistance

Multiply each side by (Resistance):

(Resistance) x (24 kilowatts) = (240 v)²

Divide each side by (24 kilowatts):

Resistance = (240 v)² / (24,000 watts)

Resistance = (57,600 / 24,000) (volt² / volt · Amp)

Resistance = 2.4 (volt/Amp)

Resistance = 2.4 Ohms

3 0
3 years ago
Inside a 30.2 cm internal diameter stainless steel pan on a gas stove water is being boiled at 1 atm pressure. If the water leve
dybincka [34]

Answer:

Q = 20.22 x 10³ W = 20.22 KW

Explanation:

First we need to find the volume of water dropped.

Volume = V = πr²h

where,

r = radius of pan = 30.2 cm/2 = 15.1 cm = 0.151 m

h = height drop = 1.45 cm = 0.0145 m

Therefore,

V = π(0.151 m)²(0.0145 m)

V = 1.038 x 10⁻³ m³

Now, we find the mass of the water that is vaporized.

m = ρV

where,

m = mass = ?

ρ = density of water = 1000 kg/m³

Therefore,

m = (1000 kg/m³)(1.038 x 10⁻³ m³)

m = 1.038 kg

Now, we calculate the heat required to vaporize this amount of water.

q = mH

where,

H = Heat of vaporization of water = 22.6 x 10⁵ J/kg

Therefore,

q = (1.038 kg)(22.6 x 10⁵ J/kg)

q = 23.46 x 10⁵ J

Now, for the rate of heat transfer:

Rate of Heat Transfer = Q = q/t

where,

t = time = (18.6 min)(60 s/1 min) = 1116 s

Therefore,

Q = (23.46 x 10⁵ J)/1116 s

<u>Q = 20.22 x 10³ W = 20.22 KW</u>

8 0
3 years ago
Which specialized science would you consult before cultivating your new field or farm for better and profitable yields? A. biote
Zepler [3.9K]
The answer is D soil cience
4 0
3 years ago
Read 2 more answers
Two 2.0-cm-diameter insulating spheres have a 6.60 cm space between them. One sphere is charged to + 76.0 nC , the other to - 30
e-lub [12.9K]

Answer:

5.2\times 10^5N/C

Explanation:

Since the two charged bodies are symmetric, we can calculate the electric field taking both of them as point charges.

This can be easily seen if we use Gauss's law, \int{E} \, dA=\frac{Q_{enclosed}}{\epsilon_o}

We take a larger sphere of radius, say r, as the Gaussian surface. Then the electric field due to the charged sphere at a distance r from it's center is given by,

E=\frac{1}{4\pi r^2} \frac{Q_{enclosed}}{\epsilon_o}

which is the same as that of a point charge.

In our problem the charges being of opposite signs, the electric field will add up. Therefore,

E_{total}=\frac{1}{4\pi\epsilon_o}\frac{q_1+q_2}{r^2}= (9\times10^9) \frac{(76+30)\times10^{-9}}{((1+3.3)\times10^{-2})^2}N/C =5.2\times10^5N/C

where, r = distance between the center of one sphere to the midpoint (between the 2 spheres)

8 0
3 years ago
Only using 10 ohm resistors come up with a way to make a battery catch fire
Margaret [11]
They catch fire with the ohm with the light from the gas with the heat and gas from radiation elects from the chemicals mixed
6 0
3 years ago
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