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Liula [17]
3 years ago
5

After walking across a carpeted floor in socks, Jim brings his finger near a metal doorknob and receives a shock. This demonstra

tes that:
Group of answer choices
Physics
1 answer:
vovangra [49]3 years ago
6 0

Answer:

After walking across a carpeted floor in socks, Jim brings his finger near a metal doorknob and receives a shock. What does this demonstrate? Frictional forces require direct contact. Electrical forces can act at a distance.

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An elevator ascends at a constant speed of 4 m/s, how much time is required for the elevator in order to travel 120 m upwards?
vlabodo [156]

We simply use the formula,

velocity =\frac{distance}{time}

Given, velocity = 4 m per s and distance = 120 m.

Substituting these values, we get

4\ m/s =\frac{120\ m}{time}\\\\\ time=\frac{120\ m}{4\ m/s} = 30\ s.

Thus, required time for the elevator in order to travel 120 m upwards is 30 s.

3 0
3 years ago
Football player A has a mass of 210 pounds and is running at a rate of 5.0 mi/hr. He collides with player B. Player B has a mass
Naddika [18.5K]

The equation for momentum is p = mv where p is the omentum, m is the mass and v is the velocity. Calculating the momentum for each football player, player A will have a momentum of 1050 lb-mi/h and player B will have a momentum of 570 lb-mi/h. Therefore, momentum of player A is greater than that of player B.

6 0
3 years ago
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What is the number of complete oscillations of a wave per second
Ira Lisetskai [31]

I believe the term Frequency is what you are looking for.  

8 0
3 years ago
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Do heavier bowling balls go faster than lighter ones?
Effectus [21]
Piper rockelle and I just got off the phone number
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3 years ago
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10. A satellites is in a circular orbit around the earth at a height of 360 km above the earth’s surface. What is its time perio
Afina-wow [57]

Answer:

Orbital speed=8102.39m/s

Time period=2935.98seconds

Explanation:

For the satellite to be in a stable orbit at a height, h, its centripetal acceleration V2R+h must equal the acceleration due to gravity at that distance from the center of the earth g(R2(R+h)2)

V2R+h=g(R2(R+h)2)

V=√g(R2R+h)

V= sqrt(9.8 × (6371000)^2/(6371000+360000)

V= sqrt(9.8× (4.059×10^13/6731000)

V=sqrt(65648789.18)

V= 8102.39m/s

Time period ,T= sqrt(4× pi×R^3)/(G× Mcentral)

T= sqrt(4×3.142×(6.47×10^6)^3/(6.673×10^-11)×(5.98×10^24)

T=sqrt(3.40×10^21)/ (3.99×10^14)

T= sqrt(0.862×10^7)

T= 2935.98seconds

4 0
3 years ago
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