Answer:
The inquiry process takes advantage of the natural human desire to make sense of the world... This attitude of curiosity permeates the inquiry process and is the fuel that allows it to continue. Process skills are not used for their own sake.
Answer:
a) -5.40 rad/s
b) -2.842 rad/s²
Explanation:
The direction is important in dealing with such questions. Clockwise is considered negative and counterclockwise is considered positive
a) Δω = final angular velocity - initial angular velocity
= -2.70 rad/s - 2.70 rad/s
= -5.40 rad/s
b) ∝ = Δω/Δt = (-5.40 rad/s)/1.90s = -2.842 rad/s²
Its d all the above your welcome
If you repeat the experiment, you will want to do it the same way to see if the results change.
HOPE THIS HELPS!!!
Let's choose the "east" direction as positive x-direction. The new velocity of the jet is the vector sum of two velocities: the initial velocity of the jet, which is
along the x-direction
in a direction
north of east.
To find the resultant, we must resolve both vectors on the x- and y- axis:




So, the components of the resultant velocity in the two directions are


So the new speed of the aircraft is:
