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STatiana [176]
3 years ago
14

1) A tourist accidentally drops a camera from a 50.0 m high bridge. What is the speed of the camera as it hits the water? *

Physics
1 answer:
Vesnalui [34]3 years ago
7 0

Question:

1) A tourist accidentally drops a camera from a 50.0 m high bridge. What is the speed of the camera as it hits the water? *

Answer:

28.0 m/s

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How long will it take for a spacecraft traveling at
zzz [600]

Answer:

16  2/3 hr

Explanation:

250 000 km / 15 000 km/hr =  16 2/3 hours

5 0
2 years ago
Two charged particles are placed 2.0 meters apart. The first charge is +2.0 E-6 C, and the second charge is +4.0 E-6 C. What is
ipn [44]
F = kq1q2/r^2 

<span>q1 is first charge </span>
<span>q2 is second charge </span>
<span>k is 9 E9 </span>
<span>r is distance between them </span>

<span>F = (9E9)(2 E-6)(4 E-6)/2^2 = 0.018 N </span>

<span>A postive answer indicates a repulsive force</span>
4 0
3 years ago
An emission ray has a frequency of 5.10 × 10¹Ê Hz. Given that the speed of light is 2.998 × 10§ m/s, what is the wavelength of t
scoundrel [369]
The answer is 5.88 · 10⁻⁷<span> m.</span>

To calculate this we will use the light equation:

v = λ · f,
where:
v - the speed of light (units: m/s)
<span>λ - the wavelength of the ray (units: m)
</span>f - the frequency of the ray (units: Hz = 1/s <span>since Hz means cycles per second (f=1/T))
</span>
It is given:
f = 5.10 · 10¹⁴ Hz = 5.10 · 10¹⁴<span> 1/s
v = 2.998 </span>· 10⁸<span> m/s
</span><span>λ = ?
</span>
If v = λ · f, then λ = v ÷ f:
λ = 2.998 · 10⁸ m/s ÷ 5.10 · 10¹⁴ 1/s
   = 0.588 · 10⁸⁻¹⁴ · m
   = 0.588 · 10⁻⁶ m
   = 5.88 · 10⁻⁷ m
6 0
3 years ago
A 4.0-kg falcon catches a 1.0-kg dove from behind in midair. What is their velocity after impact if the falcon’s velocity is ini
Grace [21]

Answer:

V = 2.8 m/s

Explanation:

It is given that,

Mass of falcon, m_1=4\ kg

Mass of dove, m_2=1\ kg

Initial velocity of falcon, u_1=3\ m/s

Initial velocity of dove, u_2=2\ m/s

When the falcon catches the dove, the momentum remains conserved. Using the formula for the conservation of momentum as :

m_1u_1+m_2u_2=(m_1+m_2)V

V is the velocity after impact

V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}

V=\dfrac{4\times 3+1\times 2}{(4+1)}

V = 2.8 m/s

So, their velocity after the impact is 2.8 m/s. Hence, this is the required solution.

7 0
3 years ago
Betty drew the life cycle of a butterfly for a science exhibition. The life cycle showed the various stages of growth before the
77julia77 [94]

Answer:

D.physical model

Explanation:

it is the evolution of butterfly

7 0
3 years ago
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