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STatiana [176]
3 years ago
14

1) A tourist accidentally drops a camera from a 50.0 m high bridge. What is the speed of the camera as it hits the water? *

Physics
1 answer:
Vesnalui [34]3 years ago
7 0

Question:

1) A tourist accidentally drops a camera from a 50.0 m high bridge. What is the speed of the camera as it hits the water? *

Answer:

28.0 m/s

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friction force is the opposition to the motion of surfaces sliding across each other. what is one factor that affects the amount
ruslelena [56]

Answer

Nature of the surfaces.


Explanation

Friction is the the force that opposes motion between two surfaces that are in relative motion. If two objects are in contact, one of it or both must be in motion for friction to exist.

Friction is affected by a number of factors.

One is the weight of the object. The more the weight of the object the higher the friction between it and the surface.

The other factor is the nature of the surfaces. Rough surfaces contribute to high friction while smooth surfaces reduces the friction between surfaces.  

3 0
3 years ago
If a total force exerted by water in a container with a bottom area of 2 square meters is 450 newtons, what's the water pressure
m_a_m_a [10]

its B 0.225kPa using the formula p=f/A then change the pascals into kpa

7 0
3 years ago
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HII!!! I need serious help with this assignment so I'm offering half my points so pLS accurately answer!! SO for this assignment
ehidna [41]

Answer:

Hey, I'm not sure I understand exactly what your assignment is but hopefully this helps . . .

put the other end against the side of the bubls base to light up the light bulb.

This will act as the bulbs conductor, lighting up bc you are making a complete electrical circuit between positive and negative terminals of the battery.

Ok hopefully this helps you out

3 0
2 years ago
A rotating cylinder about 16 km long and 7.8km in diameter is designed to be used as a space colony.
Semmy [17]

Answer:

0.05 rad/s

Explanation:

7.8 km = 7800 m

For the residents inside the space cylinder to experience the same gravitation acceleration g = 9.81m/s2 on Earth, the centripetal acceleration must be the same as g

a = g

But centripetal acceleration is product of angular velocity squared and radius of rotation r

\omega^2r = 9.81

\omega^2 d/2 = 9.81

\omega^2 = \frac{2*9.81}{d} = \frac{19.62}{7800} = 0.0025

\omega = \sqrt{0.0025} = 0.05 rad/s

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3 years ago
Plzzz Helppppppppppppppppppp
White raven [17]

1gw

that's the answer tnx

4 0
3 years ago
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