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BaLLatris [955]
3 years ago
6

Which is something that a PURE SUBSTANCE and a SOLUTION have in common?

Chemistry
1 answer:
zhuklara [117]3 years ago
8 0

D) They both look uniform (the same) throughout.

<h3>Further explanation</h3>

Pure substance can be any element or compound and is formed from one type of atom/molecule only

Meanwhile, the solution is included in a mixture consisting of 2 or more pure substance

Pure substance can be formed through a chemical process while the mixture is through a physical process

Mixture can be separated by physical processes into components of pure substance while pure substance cannot

The mixture itself consists of a homogeneous and heterogeneous solution

The mixture can be divided into a homogeneous mixture if the composition/ratio of each substance in the mixture is the same and a heterogeneous mixture if the ratio of the composition of the substances is not the same (can be varied) in each place.

Mixtures can also be divided into solutions, suspensions, and colloids based mainly on the size of the particles

Homogeneous mixture = Solution

Heterogeneous mixture = suspension, and

The mixture is located between suspension and solution = Colloid

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That is called COMPOUND microscope....
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What two atoms are held together by a covalent bond in NaHCO3
gtnhenbr [62]

Answer: covalent bond is the force of attraction that holds together two atoms that share a pair of valence electrons. Covalent bonds form only between atoms of nonmetals. The two atoms that are held together in a covalent bond may be atoms of the same element or different elements.

Explanation:

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3 years ago
32P can be used to make any nucleotide (A, C, G, or T) radioactive. Which of the following explains why this is true?
xxMikexx [17]
B. The answer is: All nucleotides have a phosphorus atom that can be replaced with 32P.

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3 years ago
What is the age of mummified primate skin that contains 8.25% of the original quantity of 14C?
rjkz [21]

Answer:

20619.4793 years

Explanation:

The half life of carbon-14 = 5730 years

The formula for the half life for a first order kinetic reaction is:

t_{1/2}=\frac {ln\ 2}{k}

Where,  

t_{1/2} is the half life

k is the rate constant.

Thus rate constant is:

5730 years=ln(2)/k

k = 1.21×10⁻⁴ years ⁻¹

Using integrated rate law as:

ln\ \frac {A_t}{A_0}=-k\times t

Where,

A_t is the concentration at time t

A_0 is the initial concentration

Given that the final concentration contains 8.25 % of the original quantity which means that:

\frac {A_t}{A_0}=0.0825

So,

ln(.0825)= -1.21×10⁻⁴×t

<u> t = 20619.4793 years</u>

<u></u>

8 0
3 years ago
Please someone help me to solve this problem​
Zinaida [17]

Answer:

(a) The final pressure of the sample becomes one-fourth of the original pressure.

(b) The pressure of the sample remains unchanged.

(c) The final pressure of the sample becomes four times of the original pressure.

Explanation:

(a)

P_{2}=\frac{P_{1}V_{1}T_{2}}{T_{1}V_{2}}

The volume of sample doubled and kelvin temperature halved.

V_{2}=2V_{1}

T_{2}=\frac{1}{2}T_{1}

P_{2}=\frac{P_{1}\times V_{1}\times \frac{1}{2}T_{1}}{T_{1}\times2V_{1}}=\frac{P_{1}}{4}

Therefore, the final pressure of the sample becomes one-fourth of the original pressure.

(b)

Volume and temperature of sample doubled.

V_{2}=2V_{1}

T_{2}=2T_{1}

P_{2}=\frac{P_{1}\times V_{1}\times 2T_{1}}{T_{1}\times2V_{1}}={P_{1}}

Therefore, the pressure of the sample unchanged.

(c)

Volume of sample halved and temperature double.

V_{2}=\frac{1}{2}V_{1}

T_{2}=2T_{1}

P_{2}=\frac{P_{1}\times V_{1}\times 2T_{1}}{T_{1}\times \frac{1}{2}V_{1}}={4P_{1}}

Therefore, the pressure of the sample becomes four times of the original pressure.

6 0
3 years ago
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