A comet speeds up as it approaches the Sun. Which statement about its kinetic energy is correct option is - (1) The comet has no kinetic energy because it is in outer space.
- Large ice and dust-based bodies known as comets circle the Sun. These ancient objects, which are best known for their long, streaming tails, are relics from the solar system's birth 4.6 billion years ago. The majority of comets are located outside of our solar system. Some are found in the Kuiper Belt, a vast disc that extends past Neptune's orbit. These are known as short-period comets. They orbit the Sun in lesser than 200 years.
- The Outermost Layer, the solar system's sphere-shaped outer edge, which is nearly 50 times further from the Sun than the Kuiper Belt, is home to additional comets. Because of how much longer it takes them to orbit the Sun, these are known as long-period comets. The comet with the longest known orbit completes one orbit in excess of 250,000 years.
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Answer:
1. 12 V
2a. R₁ = 4 Ω
2b. V₁ = 4 V
3a. A = 1.5 A
3b. R₂ = 4 Ω
4. Diagram is not complete
Explanation:
1. Determination of V
Current (I) = 2 A
Resistor (R) = 6 Ω
Voltage (V) =?
V = IR
V = 2 × 6
V = 12 V
2. We'll begin by calculating the equivalent resistance. This can be obtained as follow:
Voltage (V) = 12 V
Current (I) = 1 A
Equivalent resistance (R) =?
V = IR
12 = 1 × R
R = 12 Ω
a. Determination of R₁
Equivalent resistance (R) = 12 Ω
Resistor 2 (R₂) = 8 Ω
Resistor 1 (R₁) =?
R = R₁ + R₂ (series arrangement)
12 = R₁ + 8
Collect like terms
12 – 8 =
4 = R₁
R₁ = 4 Ω
b. Determination of V₁
Current (I) = 1 A
Resistor 1 (R₁) = 4 Ω
Voltage 1 (V₁) =?
V₁ = IR₁
V₁ = 1 × 4
V₁ = 4 V
3a. Determination of the current.
Since the connections are in series arrangement, the same current will flow through each resistor. Thus, the ammeter reading can be obtained as follow:
Resistor 1 (R₁) = 4 Ω
Voltage 1 (V₁) = 6 V
Current (I) =?
V₁ = IR₁
6 = 4 × I
Divide both side by 4
I = 6 / 4
I = 1.5 A
Thus, the ammeter (A) reading is 1.5 A
b. Determination of R₂
We'll begin by calculating the voltage cross R₂. This can be obtained as follow:
Total voltage (V) = 12 V
Voltage 1 (V₁) = 6 V
Voltage 2 (V₂) =?
V = V₁ + V₂ (series arrangement)
12 = 6 + V₂
Collect like terms
12 – 6 = V₂
6 = V₂
V₂ = 6 V
Finally, we shall determine R₂. This can be obtained as follow:
Voltage 2 (V₂) = 6 V
Current (I) = 1.5 A
Resistor 2 (R₂) =?
V₂ = IR₂
6 = 1.5 × R₂
Divide both side by 1.5
R₂ = 6 / 1.5
R₂ = 4 Ω
4. The diagram is not complete
Answer:
The value is
Explanation:
From the question we are told that
The mass of the block is
The force exerted is
The frequency is
Generally the spring constant of the spring is mathematically represented as
=>
=>
Generally the spring constant is also mathematically represented as
=>
=>
Answer:
0.53 N, 25.6°
Explanation:
side of triangle, a = 1.2 m
q = 7 μC
q1 = - 8 μC
q2 = - 6 μC
Let F1 be the force between q and q1
By using the coulomb's law
F1 = 0.35 N
Let F2 be the force between q and q2
By using the coulomb's law
F2 = 0.26 N
Write the forces in the vector form
Net force
Magnitude of the force
F = 0.53 N
Direction of force with x axis
θ = 25.6°
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